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Tema [17]
3 years ago
7

Suppose you roll one die. What is the probability of rolling a multiple of 3?

Mathematics
1 answer:
lorasvet [3.4K]3 years ago
5 0
The sample space in rolling a die is 6 since the cube has six sides that are numbered from 1 to 6. Of these numbers, only 3 and 6 are the multiple of 3. Thus, the probability of obtaining a multiple of 3 is 2/6 or also equal to 1/3. 
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Explain how you could use a number line to determine -5 -(-3)<br><br> What is the difference?
AURORKA [14]

Answer:

The difference is -2

7 0
3 years ago
Through (4,-4) ; perpendicular to 6y=x-12
BARSIC [14]

y = mx + b

m = slope and b = y-intercept


We can arrange 6y = x - 12 in the form of y = mx + b

                  6y = x - 12

                    y = 1/6(x) - 2

Slope of y = 1/6(x) - 2 is 1/6. Taking the negative reciprocal of the slope we get the slope for the perpendicular line.

Negative reciprocal of 1/6 is -6.

The equation for the perpendicular line is

                  y = -6x + b

To find b we can plug in the x and y values of (4,-4) into it since it passes through those coordinates

                -4 = -6(4) + b

                 b = -4 + 6(4)

                 b = -4 + 24

                 b = 20

So the equation for the perpendicular line is y = -6x + 20

3 0
3 years ago
Find the value of m and b for the equation 0=-9x+5y+25
lukranit [14]

Answer:

X= -5

Y=-2.7

Step-by-step explanation:

YOU DO THIS BY SUBTRACTING 25 ON THE RIGHT SIDE TO THE LEFT ONLY LEAVING YOU WITH VARIABLES.

THEN YOU SUBSTITUTE ZERO INTO Y TO FIND X THEN SUBTITUTE ZERO INTO X TO FIND Y

BTW SUBSTITUTE ONE INTO THE VARIABLE YOU ARE FINDING

8 0
3 years ago
2x² - 5x+1 has roots alpha and beta. Find alpha⁴+beta⁴ without solving the equation.
shepuryov [24]

Answer:

Step-by-step explanation:

\alpha+\beta=\dfrac{5}{2} \\\\\alpha*\beta=\dfrac{1}{2} \\\\\alpha^2+\beta^2=\dfrac{21}{4} \ (see\ previous\ post)\\\\(\alpha+\beta)^4=\dfrac{625}{16} \\\\=\alpha^4+\beta^4+4*\alpha^3*\beta+6*\alpha^2*\beta^2+4*\alpha*\beta^3\\\\=\alpha^4+\beta^4+4*(\alpha*\beta)(\alpha^2+\beta^2)+6*\alpha^2*\beta^2\\\\\alpha^4+\beta^4=(\alpha+\beta)^4-4*(\alpha*\beta)(\alpha^2+\beta^2)-6*\alpha^2*\beta^2\\\\= \dfrac{625}{16} -4*\dfrac{1}{2} *\dfrac{21}{4} -6*(\dfrac{1}{2})^2 \\\\

= \dfrac{625}{16}- \dfrac{168}{16}-\dfrac{24}{16}\\\\\\= \dfrac{433}{16}

7 0
3 years ago
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PIT_PIT [208]

Answer:

0.4

Step-by-step explanation:

just solve it like an equation.

4 0
3 years ago
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