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VARVARA [1.3K]
3 years ago
8

A hotel wants to put a fence around a circular spa. The radius of the spa is 5/√2-1 feet. If the fence is built along the immedi

ate edge of the spa, what is the perimeter of the fence? (Recall that the
perimeter of a circle is 2πr , where r is the radius of the circle.)
Physics
1 answer:
Vlad [161]3 years ago
5 0
It is important to look at all the information's that are given in the question very closely. Let us write them write first.

Radius of the spa = <span>5/√2-1 feet
Now
Perimeter of the circle = </span><span>2πr
                                    = 2</span>π (5/√2-1) 
                                    = <span>π(5/(√2-1)*(√2+1)/(√2+1) </span>
<span>                                    = 2π(5/(√2+1))/(2-1) </span>
<span>                                    = 10π(√2+1)  

I hope that the procedure is clear enough for you to understand.</span>
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A 20-cm-long stick of m = 0.600 kg is lifted by a rope tied 5.0 cm from the upper end. The other end touches a smooth floor. The
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2 years ago
Kyle, a 95.0 kg football player, leaps straight up into the air (with no horizontal velocity) to catch a pass. He catches the 0.
babymother [125]

Answer:

The initial speed of the ball was 26.2 m/s

Explanation:

When the football player is in the air at his maximum height the vertical component of velocity is zero, To obtain the horizontal velocity when the player catches the ball we need to apply the linear momentum conservation theorem:

m_1*v_{o1}+m_2*v_{o2}=m_t*v_f\\0.430kg*(v)+m_2*(0)=mt*vt

we need to obtain the time taken to go down.

y=Y_o+v_o*t-\frac{1}{2}g*t^2\\\\0=0.589-4.9t^2\\solving:\\t_1=0.346s\\

We have a horizontal displacement and the time taken to stop, so:

v_f=\frac{d}{t}=\frac{0.0409m}{0.346s}=0.118m/s

so:

0.430kg*(v)+m_2*(0)=(m1+m2)*vt\\v=\frac{(95.0kg+0.430kg)*0.118m/s}{0.430kg}\\\\v=26.2m/s

8 0
3 years ago
If you subtract vector 3.7 cm at 45° North of East from vector 4.5 cm at 57° West of North using a scale drawing, what is the re
Gelneren [198K]

The resultant vector is 5.2 cm at a direction of 12⁰ west of north.

<h3>Resultant of the two vectors</h3>

The resultant of the two vectors is calculated as follows;

R = a² + b² - 2ab cos(θ)

where;

  • θ is the angle between the two vectors =  45° + (90 - 57) = 78⁰
  • a is the first vector
  • b is the second vector

R² = (3.7)² + (4.5)² - (2 x 3.7 x 4.5) cos(78)

R² = 27.02

R = 5.2 cm

<h3>Direction of the vector</h3>

θ = 90 - 78⁰

θ = 12⁰

Thus, the resultant vector is 5.2 cm at a direction of 12⁰ west of north.

Learn more about resultant vector here: brainly.com/question/28047791

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3 0
1 year ago
James Bond is trying to escape his enemy on a speedboat but
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Answer:

100 m/s

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Initial speed of Bond's boat is 0 as it won't start and remains stationary in the water. The initial speed of enemy's boat is 50 m/s. After the collision, enemy boat is  completely stationary. Let v₁ is speed of bond's boat.

It is the concept of the conservation of momentum. It remains conserved. So,

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Putting all the values, we get :

0+(2m_1)50=m_1v_1+(2m_2)(0)\\\\100m_1=m_1v_1\\\\v_1=100\ m/s

So, Bond's boat is moving with a speed of 100 m/s after the collision.

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