An average cyclist generates about 183 watts while doing 19 mph or 30.4 kph. Power = force × velocity. Force of a pedalling applied by a human for achieving 30.4 kph = 183/8.44 = 21.68 newtons. This is for upright bicycles.
Answer:
a= 4.14 m/s²
Explanation
We calculate the weight component parallel to the displacement of the block:
We define the x-axis in the direction of the inclined plane , 25° to the horizontal.
W= m*g : Total block weight
Wx= W*sen25°= m*g* sen25°
We apply Newton's second law :
∑F = m*a (Formula 1)
∑F : algebraic sum of the forces in Newton (N)
m : mass in kilograms (kg)
a : acceleration in meters over second square (m/s²)
Problem development
We apply the formula (1) to calculate the acceleration of the block:
∑Fx = m*a
Wx = m*a
m*g* sen25° = m*a : We divide by m on both sides of the equation
g* sen25° = a
a = g* sen25° = 9.8* sen25° = 4.14 m/s²
Answer:
Solid sphere will reach first
Explanation:
When an object is released from the top of inclined plane
Then in that case we can use energy conservation to find the final speed at the bottom of the inclined plane
initial gravitational potential energy = final total kinetic energy
now we have
here k = radius of gyration of object
also for pure rolling we have
so now we will have
so we will say that more the value of radius of gyration then less velocity of the object at the bottom
So it has less acceleration while moving on inclined plane for object which has more value of k
So it will take more time for the object to reach the bottom which will have more radius of gyration
Now we know that for hoop
k = R
For spherical shell
For solid sphere
So maximum value of radius of gyration is for hoop and minimum value is for solid sphere
so solid sphere will reach the bottom at first
The pressure value is given by the equation,
Where,
represents the density of the liquid
g= gravity
h= Heigth
A) For the measurement of the guage pressure we have the data data,
Replacing we get,
P_g = 12395Pa[/tex]
In order to find the Absolute pressure, we perform a sum between the atmospheric pressure and that of the Gauge,
B) The atmospheric pressure at sea level is 101325Pa, assuming ideal conditions, we will take this pressure for our calculation, so