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Stels [109]
3 years ago
12

A car salesman receives $50 for each car sale plus 2% of the purchase price. How much must a car sell for in order for the sales

person to earn at least $500?
Mathematics
2 answers:
Kamila [148]3 years ago
8 0
We simply take the amount he needs no earn ($500) subtract what he gets for each sale ($50) and divide with the percentage he gets (2% = 0.02)

500-50 = 450
450/0.02 = 22500

The salesperson has to sell a car for $22500 in order to earn $500 himself
otez555 [7]3 years ago
4 0

Answer:

Car must be sell for sales price of at least of $22,500.

Step-by-step explanation:

Given :Salesman receives $50 for each car sale plus 2% of the purchase price. That can mathematically be represented as:

\$50+2\%\text{Sales price of the car}=T

Money received by the salesperson =T

Let the sale price of the car be P

\$50+2\%\text{Sales price of the car}\geq \$500

\$50+\frac{2}{100}\times P=\$500

P=\$22,500

P ≥ $22,500

Car must be sell for sales price of at least of $22,500.

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Apply each of the four counting/sampling methods (with replacement and with ordering, without replacement and with ordering, wit
dusya [7]

Answer:

Step-by-step explanation:

I will illustrate this solution with a unique birthday party situation between Jane (the celebrant) and her 10 friends.

In the said party , we will assume that Jane only has 5 chocolates to share among her friends

i. Assuming that the 5 chocolates are of the same type, if she doesn't want to give any friend more than one piece of chocolate, the situation here is said to be WITHOUT REPLACEMENT & UN-ORDERED

n = 10 and k = 5

Total number of possible combinations becomes,

(\left {n} \atop {k}} \right. )=(\left {10} \atop {5}} \right. )=252

ii. Assuming that the 5 pieces of chocolate are of the same type and she is willing to give a friend more than one piece of chocolate, the situation is said to be WITH REPLACEMENT & UN-ORDERED

n = 10 and k = 5

Total number of possible combinations becomes,

(\left {n+k-1} \atop {k}} \right. )=(\left {14} \atop {5}} \right. )=2002

iii. Assuming that the 5 pieces of chocolate are of different types and she isn't willing to give any friend more than one piece of chocolate, the situation is said to be WITHOUT REPLACEMENT & ORDERED

n = 10 & k = 5

Total number of possible combinations becomes,

P\left {n} \atop {k}} \right=P\left {10} \atop {5}} \right. =30240

iv. Assuming the the 5 pieces of chocolate are of different types, if she is willing to give a friend more than one piece of chocolate, the situation is said to be WITH REPLACEMENT & ORDERED

n = 10 AND k = 5

Total number of combinations becomes

n^k=10^5=100,000

Sampling with replacement means that one friend can be sampled more than once i.e: A friend receives a piece of chocolate more than once

The order dictates how the sampling is applied.

3 0
3 years ago
3 x A = 30 + 30<br><br> it’s a 3rd grade problem but don’t know the answer
xenn [34]

Answer: A=20

Step-by-step explanation:

3×A=30+30............eqn 1

3A=60

A=60/3

A=20

Substitute A=20 into equation 1

3x20= 30+30

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gtnhenbr [62]

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BigorU [14]

Answer:

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