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lord [1]
4 years ago
12

How much (in mL) 12.1 M solution of hydrochloric acid would be required to make 500 mL of a 2.5 M solution

Chemistry
1 answer:
victus00 [196]4 years ago
6 0

Answer:

Volume of the concentrated solution, which is needed is 103.30 mL

Explanation:

Let's apply the formula for dilutions to solve the problem

Conc. Molarity . Conc. volume = Dil. Molarity . Dil volume

12.1 M . Conc. volume = 2.5 M . 500 mL

Conc. volume = (2.5 M . 500 mL) / 12.1M

Conc. volume = 103.30 mL

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Vinvika [58]

Answer:

K is the symbol for potassium

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3 years ago
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A 5-gal, cylindrical open container with a bottom area of 120 square inches is filled with glycerin and rests on the floor of an
aleksandrvk [35]

Answer:

a)  68.9 b/ ft²

b)  57.416

Explanation:

Volume of the cylindrical open container V = 5 gal

= (5)(231)

= 11155 in³

different diagrammatic expression has been shown in the attached file below for clear understanding.

Area A = 120 in²

V = hA

    = \frac{1155}{120}

    =  9.625 in

Upward acceleration , a_z= 3ft/s^2

\frac{dp}{dz} = \rho (g + a_z)

dp= -\rho (g + a_z)dz

\int\limits^P}_0 \,dp= -\rho (g + a_z)  \int\limits^0_h \,   dz

P_b = -\rho (g + a_z) h

= (2.4)*(32.2+3) (\frac{9.625}{12})

= 68.9 b/ ft²

b) The flowchart for the resultant force is shown in the  diagram below:

with that:

F_f = P_bA

F_f =\frac{(68.9)(120)}{(144)}

F_f =57.416

Thus,  the resultant force that the container exert on the floor of the elevator during this acceleration = 57.416

5 0
3 years ago
Is a hydrogel a smart polymer/stimuli-responsive polmer?​
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Polymer scientists have been trying to mimic this behavior by creating so called smart polymers. ... One of the most important classes of stimuli-responsive polymers used for controlled drug delivery is crosslinked polymer networks, e.g., hydrogels and microgels.
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Pavel [41]

Answer:

C: Mg

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Carbon(C) can hybridized on sp, sp2 and sp3 simply because it's valence shell gives room for it.

For silicon(si), when forming covalent bonds with other atoms, it's 3s and 3p orbitals are mixed with each other to form new hybrid orbitals.

Magnesium in itself doesn't hybridized except in magnesium hydrides.

Boron orbitals(B): when boron forms bonds with three other atoms like borazine, they are hybridized to either the sp2 or hybridized to the sp3 which occurs when boron forms bonds with four atoms just as is in metal borohydrides.

7 0
3 years ago
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