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Dmitrij [34]
3 years ago
15

1. The center of the atom is called the

Chemistry
1 answer:
34kurt3 years ago
3 0
The nucleus is the center of the atom!
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Where would a primary producer be located in a food chain?
vfiekz [6]

Answer:

The primary producer would be at the bottom of the food chain.

Explanation:

4 0
4 years ago
Read 2 more answers
2) what is the mass of 6.02 x 1023 atoms of arsenic?
zzz [600]
Data:
Arsenic Molar Mass = 74,9216 ≈ 75 u (<span>atomic mass unit)</span>

Solving:

1 mole of arsenic → 75g ------------ 6,02*10²³ molecules
..................................X -------------- 1 molecule

6,02*10²³X = 75
x = \frac{75}{6,02*10^{23}}
\boxed{x \approx 1,24*10^{24}grams}
6 0
3 years ago
g The reaction; 4 Ag(s) + O2(g) ----&gt; 2 Ag2O(s), is exothermic. Which statement about the reaction is correct? (A) It is spon
melomori [17]

Answer:

The correct answer is B. It is spontaneous only at low temperatures.

Explanation:

In thermodynamics, the Gibbs free energy is a thermodynamic potential that can be used to calculate the maximum of reversible work that may be performed by a thermodynamic system at a constant temperature and pressure.

The spontaneity of a reaction is given by the equation:

ΔG = ΔH - TΔS

where:

ΔH: enthalpy variation

T: absolute temperature

ΔS: entropy variation

As the reaction is exothermic, ΔH<0

As the reaction order increases (the reagents are solid and gas and their product is solid), ΔS<0

Therefore, the reaction will be spontaneous when ΔG is negative.

ΔG = ΔH - TΔS

That is, the entropy term must be smaller than the enthalpy term.

Hence, the reaction will be spontaneous only at low temperatures.

4 0
3 years ago
An engine operates on a Carnot cycle that uses 1mole of an ideal gas as the
sattari [20]

Answer:

Step 1;

q = w = -0.52571 kJ, ΔS = 0.876 J/K

Step 2

q = 0, w = ΔU = -7.5 kJ, ΔH = -5.00574 kJ

Explanation:

The given parameters are;

P_i = 100 N·m

T_i = 327 K

P_f = 90 N·m

Step 1

For isothermal expansion, we have;

ΔU = ΔH = 0

w = n·R·T·ln(P_f/P_i) = 1 × 8.314 × 600.15 × ln(90/100) = -525.71

w ≈<em> -0.52571</em> kJ

At state 1, q = w = -0.52571 kJ

ΔS = -n·R·ln(P_f/P_i) = -1 × 8.314 × ln(90/100) ≈ 0.876

ΔS ≈ 0.876 J/K

Step 2

q = 0 for adiabatic process

ΔU = 25×(27 - 327) = -7,500

w = ΔU = <em>-7.5 kJ</em>

ΔH = ΔU + n·R·ΔT

ΔH = -7,500 + 8.3142 × 300 = -5,005.74

ΔH = ΔU = <em>-5.00574 kJ</em>

6 0
3 years ago
A solution prepared by dissolving 0.100 mole of propionic acid in enough water to make 1.00 L of solution is observed to have a
torisob [31]

Answer:

C) k_a=1.3\times 10^{-5}

Explanation:

pH is defined as the negative logarithm of the concentration of hydrogen ions.

Thus,  

pH = - log [H⁺]

The expression of the pH of the calculation of weak acid is:-

pH=-log(\sqrt{k_a\times C})

Where, C is the concentration = 0.5 M

Given, pH = 2.94

Moles = 0.100 moles

Volume = 1.00 L

So, Molarity=\frac{Moles}{Volume}=\frac{0.100}{1.00}\ M=0.100\ M

C = 0.100 M

2.94=-log(\sqrt{k_a\times 0.100})

\log _{10}\left(\sqrt{k_a0.1}\right)=-2.94

\sqrt{0.1}\sqrt{k_a}=\frac{1}{10^{2.94}}

k_a=1.3\times 10^{-5}

4 0
3 years ago
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