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3 years ago

1. If temperature is increased, the number of collisions per second

Chemistry

1 answer:

andrey2020 [161]3 years ago

4 0

Answer:

Increases

Explanation:

Increasing the temperature increases reaction rates because of the disproportionately large increase in the number of high energy collisions.

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The cylinder of aluminum in class was approximately 13mm in circumference and 42mm in length. What would be it's approximate mas

Roman55 [17]

Answer:

Mass, m = 1.51 grams

Explanation:

It is given that,

The circumference of Aluminium cylinder, C = 13 mm = 1.3 cm

Length of the cylinder, h = 4.2 cm

We know that the density of the Aluminium is 2.7 g/cm³

Circumference, C = 2πr

$r=\dfrac{C}{2\pi}\\\\r=\dfrac{1.3}{2\pi}\\\\r=0.206\ cm$

Density is equal to mass per unit volume.

$d=\dfrac{m}{V}$

m is mass of the cylinder

V is the volume of the cylinder

$V=\pi r^2h\\\\V=\dfrac{22}{7}\times0.206^2\times 4.2\\\\V=0.5601\ cm^3$

So,

$m=d\times V\\\\m=2.7\times 0.5601\\\\m=1.51\ g$

So, the mass of the cylinder is 1.51 grams.

5 0

4 years ago

Which of the following would be appropriate reason(s) for scientists to reject atomic theory?

leonid [27]

It posed a contradiction to Quantum Theory

3 0

3 years ago

Read 2 more answers

What is the volume of 0.80 grams of o2 gas at stp? (5 points) group of answer choices 0.59 liters 0.56 liters 0.50 liters 0.47 l

Vladimir [108]

Answer:

0.56L

Explanation:

This question requires the Ideal Gas Law: $PV=nRT$ where P is the pressure of the gas, V is the volume of the gas, n is the number of moles of the gas, R is the Ideal Gas constant, and T is the Temperature of the gas.

Since all of the answer choices are given in units of Liters, it will be convenient to use a value for R that contains "Liters" in its units: $R=0.0821\frac{L\cdot atm}{mol\cdot K}$

Since the conditions are stated to be STP, we must remember that STP is Standard Temperature Pressure, which means $T=273.15K$ and $P=1atm$

Lastly, we must calculate the number of moles of $O_2(g)$ there are. Given 0.80g of $O_2(g)$ , we will need to convert with the molar mass of $O_2(g)$ . Noting that there are 2 oxygen atoms, we find the atomic mass of O from the periodic table (16g/mol) and multiply by 2: $32g\text{ }O_2=1mol\text{ }O_2$

Thus, $\frac{0.80g \text{ }O_2}{1} \frac{1mol\text{ }O_2}{32g\text{ }O_2}=0.25mol\text{ }O_2=n$

Isolating V in the Ideal Gas Law:

$PV=nRT$

$V=\frac{nRT}{P}$

...substituting the known values, and simplifying...

$V=\frac{(0.025 mol \text{ }O_2)(0.0821\frac{L\cdot atm}{mol \cdot K} )(273.15K)}{(1atm)}$

$V=0.56L \text{ } O_2$

So, 0.80g of $O_2(g)$ would occupy 0.56L at STP.

5 0

2 years ago

Read 2 more answers

How do two sublevels of the same principal energy level differ from each other?

dem82 [27]

Two sublevels of the same principal energy level differ from each other through shape and size.

There are mainly 4 energy level s, p, d and f.

The s level has one orbital and one orbital have two electrons. So the maximum number of electron in s sublevel is 2.

The p level has three orbital and one orbital have two electrons. So the maximum number of electron in s sublevel is 6.

The d level has five orbital and one orbital have two electrons. So the maximum number of electron in s sublevel is 10.

The f level has 7 orbital and one orbital have two electrons. So the maximum number of electron in s sublevel is 14.

They may be differ in magnetic level.

Thus, we concluded that Two sublevels of the same principal energy level differ from each other through shape and size.

learn more about energy level:

brainly.com/question/14654539

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3 0

1 year ago

a graduated cylinder (approximate as a regular cylinder) has a radius of 1.045 cm and a height of 30.48 cm. what is the volume o

Luba_88 [7]

Answer: 103.5 cm^3

Explanation:

8 0

3 years ago