Question

What is a27 of the sequence 15 , 10 , 5 , … ?

Answer 1

Answer:

$a_{27}=-115$

Step-by-step explanation:

The given sequence is $15,10,5,...$

The common difference is d=10-15=-5

The first term of this sequence is $a_1=15$

We want to find the 27th term in this sequence.

The 27th term is given by:

$a_{27}=a_1+26d$

We substitute the values to get:

$a_{27}=15+26(-5)$

$a_{27}=15-130=-115$