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Semenov [28]
3 years ago
5

IHELP if 1 out of 5 animals are cats then how many cats are there in an ecosystem of 200 animals???​

Mathematics
1 answer:
mote1985 [20]3 years ago
3 0
There are 40 cats in the ecosystem.

You set 1/5 equal to x/200. Then you cross multiply the fractions to get 5x=200. You divide both terms by 5 to get x, which equals 40.

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scoray [572]

Answer: A

Step-by-step explanation:

4 0
3 years ago
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In ΔLMN, the measure of ∠N=90°, NL = 6. 8 feet, and LM = 9. 4 feet. Find the measure of ∠L to the nearest tenth of a degree.
egoroff_w [7]

Answer:

Step-by-step explanation:
The above is a right angled triangle
So you take the longest side
9.4^2 - 6.8^2
88.36- 46.24
sqrt of 42.12
6.4899

To the nearest tenth of a degree = 6.56.5ft



5 0
2 years ago
Please show your work
belka [17]

Answer:

W = 8.2 cm

Step-by-step explanation:

The perimeter formula is P = 2W + 2L and here the perimeter is 65.6 cm.

Thus, 65.6 cm = 2W + 2L.  Substituting 3W for L, we get

          65.6 cm = 2W + 2(3W) = 8W.

Solving for W by dividing both sides by 8, we get W = 65.6 cm / 8, or

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3 0
3 years ago
Read 2 more answers
Select all the rates that are unit rates.
Nataly_w [17]

Answer:

\frac{2/3}{1} and \frac{3}{1}

Step-by-step explanation:

Options

\frac{1}{1/3}     \frac{2/3}{1}     \frac{2}{3}     \frac{3}{1}     \frac{1}{9}

Required

Select the unit rates

Unit rate involve two items where the first item being measured can be any positive number, but the second item must be measured in units (i.e. 1)

For clarity:

If \frac{a}{b} represents unit rate, then b = 1

Having said that:

Only \frac{2/3}{1} and \frac{3}{1} satisfy the condition of unit rates; others are not because they have a denominator other than 1

3 0
2 years ago
There is a vendor at a carnival selling bags of cotton candy. Each bag of cotton candy has the same cost. She starts each day wi
umka21 [38]

Answer:

The cost of each cotton candy bag is $4.

Step-by-step explanation:

Consider the provided information.

Let, the vendor has x dollar at the starting of each day.

Let, the cost of each cotton candy bag is y.

Now when she sells a total of 12 bags, she has $128.

x+12y=128  .....(1)

After she sells a total of 20 bags, she has $160.

x+20y=160  ....(2)

Subtract equation 1 from equation 2.

(x+20y)-(x+12y)=160-128

8y=32

y=4

Hence, the cost of each cotton candy bag is $4.

6 0
3 years ago
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