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3 years ago

Help me from 3 through 8

Mathematics

1 answer:

skad [1K]3 years ago

7 0

Answer:

3)x=−9 and x=4

4)x=−12 and x=−5

5)x=8 and x=14

6)x=−7 and x=3

7)x=-1 2/3 and x = 1/4

8)x=2/5

Step-by-step explanation:

Hope this helps

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3 years ago

Brianna is a waitress in an upscale restaurant. On Friday she waited on 12 groups of customers who spent an average of $186 per

givi [52]

Given :

Brianna is a waitress in an upscale restaurant. On Friday she waited on 12 groups of customers who spent an average of $186 per group.

Her tips averaged 18% of the total amount spent by all the groups of customers that day.

To Find :

Brianna's tip income earnings on Friday.

Solution :

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She got tip of 18% of the total amount spent by all the groups of customers.

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4 years ago

A business rents cars for $100 a day and vans for $200 a day. One day, it rented a total of 22 vehicles

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Answer:

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Step-by-step explanation:

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8 0

2 years ago

20 people applied for a job. Everyone either has a school certificate or diploma or even both. If 14 have school certificates an

STatiana [176]

Given:

Either has a school certificate or diploma or even both = 20 people

Having school certificates = 14

Having diplomas = 11

To find:

The number of people who have a school certificate only.

Solution:

Let A be the set of people who have school certificates and B be the set of people who have diplomas.

According to the given information, we have

$n(A)=14$

$n(B)=11$

$n(A\cup B)=20$

We know that,

$n(A\cup B)=n(A)+n(B)-n(A\cap B)$

$20=14+11-n(A\cap B)$

$20=25-n(A\cap B)$

Subtract both sides by 25.

$20-25=-n(A\cap B)$

$-5=-n(A\cap B)$

$5=n(A\cap B)$

We need to find the number of people who have a school certificate only, i.e. $n(A\cap B')$ .

$n(A\cap B')=n(A)-n(A\cap B)$

$n(A\cap B')=14-5$

$n(A\cap B')=9$

Therefore, 9 people have a school certificate only.

3 0

3 years ago