Question

Seven apple women, possessing respectively 20, 40, 60, 80, 100, 120, and 140

Answer 1

Answer:

The amount each took home was 20 unit currency.

Step-by-step explanation:

We are given that Seven apple women, possessing respectively 20, 40, 60, 80, 100, 120, and 140  apples, went to market and sold all their apples at the same price, and each  received the same sum of money.

Formula  : $a \times n + (n - 1)$, $(a + b)\cdot n + (n - 2)$, $(a + 2 \cdot b) \cdot n + (n - 3)$, $(a + 3 \cdot b) \cdot n + (n - 4)$, $(a + 4 \cdot b) \cdot n + (n - 5)$, $(a + 5 \cdot b) \cdot n + (n - 6)$, $(a + 6 \cdot b) \cdot n + (n - 7)$

$a \cdot n + (n - 1) = 20$

$(a + b) \cdot n + (n - 2)=40$

$(a + 2 \cdot b) \cdot n + (n - 3) = 60$

$(a + 3 \cdot b) \cdot n + (n - 4) = 80$

$(a + 4 \cdot b) \cdot n + (n - 5) = 100$

$(a + 5 \cdot b) \cdot n + (n - 6) = 120$

$(a + 6 \cdot b) \cdot n + (n - 7) = 140$

On solving :

n = 7, a = 2, b = 3

So,

$2 \times 7 + 6 = 20$

$5 \times 7 + 5=40$

$8 \times 7 + 4 = 60$

$11 \times 7 + 3 = 80$

$14 \times 7 + 2 = 100$

$17 \times 7 + 1 = 120$

Based on market pricing if groups of apples are sold at 1 unit currency for 7, and extras are sold for 3 unit currency per extra 1, we have the amount :

2×1 + 6×3 = 20

5×1 + 5×3=20

8×1 + 4×3 = 20

11×1 +  3×3 = 20

14×1 + 2×3 = 20

17×1 + 1×3 = 20

20×1 = 20

Therefore, the amount each took home was 20 unit currency.