Answer:
<E = 36 degrees (Answer B)
Step-by-step explanation:
Recall that the addition of all internal angles in a quadrilateral must equal 360 degrees. Then we can write the equation that states this as:
<E + <F + <G + <H = 360
Notice as well that we are dealing with an isosceles trapezoid, so there is a symmetry along the line that passes through the midpoints of sides FG and EH (the two bases). That means that the measures of angles <F = <G and <E = <H .
The previous equation then can be written as:
<H + <G + <G + <H = 360
Also, since we are told that <G = 4 <H, we can use this info in the equation as shown below:
<H + 4 <H + 4 <H + <H = 360
10 <H = 360
divide both sides by 10 to isolate <H
<H = 360 / 10
<H = 36
Since as we mentioned, <E equals <H, we can state that
the measure of <E = 36 degrees (Answer B)
C + d = 180°(supplementary angle)
C = 5d
5d + d = 180°
6d = 180°
d = 180°/6
d = 30°
Since C = 5d,
C = 5 x 30°
Therefore, C = 150°
Hope this helps
Please mark brainliest :):)
9514 1404 393
Answer:
15 m
Step-by-step explanation:
The area of the square attached to the third side is the sum of the areas of the other squares:
81 m² +144 m² = 225 m²
The side length is the square root of this:
? m = √(225 m²) = 15 m
The length of the indicated side is 15 m.
Step One
Find the area of the rectangle
Area = L * W
Area = 89 cm * 70 cm
Area = 6230 cm^2
Step Two
What is the formula for the two end semicircles?
Two semicircles = 1 whole circle
Area of any circle = pi * r^2
Step Three
Find the area of the circle
r = the width / 2 This may not be true. You need the diagram. If the circles are drawn on the length then use r = the length / 2
r = 70/2 = 35 cm
Area of circle = pi * r^2
Area of circle = 3.14 * 35^2
Area of circle = 3846.5
Step Four
Find the total area
The total area = Area of the rectangle + area of circle
The total area = 6230 + 3846.5
The total area = 10076.5 cm^2 <<<< Answer
If it is on sale for 15%, then you are paying 85% (100-15) of the original price.
To find 85% of 850, you do 850*.85 to get $722.50
Hope this helps