Answer:
x = 11.4
Step-by-step explanation:
14.12 = 
( 3.6x - 12.8 )
Rewrite so that the equation is entirely in decimals;
14.12 = 0.5( 3.6x - 12.8 )
Distribute;
14.12 = 1.8x - 6.4
Inverse operations;
14.12 = 1.8x - 6.4
+6.4 +6.4
20.52 = 1.8x
/1.8 /1.8
11.4 = x
An equation is formed of two equal expressions. There is no solution set of the equation 3x+13 = 3(x+6)+1.
<h3>What is an equation?</h3>
An equation is formed when two equal expressions are equated together with the help of an equal sign '='.
The equation can be solved in the following manner,
Since both the sides of the equation are the same in terms of variable and the constant terms are not the same. Therefore, there is no solution set of the equation 3x+13 = 3(x+6)+1.
Learn more about Equation:
brainly.com/question/2263981
We know that
Inverse Variation is a<span> relationship between two variables in which the product is a constant
so
let
x------> a pitch of a musical instrument
y------> </span><span>the wavelength
x*y=k
find the value of k
for x=</span><span>220 hertz y=3 ft
</span><span>x*y=k
220*3=k
k=660
</span>for x=165 hertz y=4 ft
x*y=k
165*4=660
k=660<span>
the answer part a) is
</span><span>the type of variation between pitch and wavelength is an inverse variation
</span>
part b) <span>What is the pitch when the wavelength is 5 feet?
x=?
y=5 ft
k=660
x*y=k------> solve for x
x=k/y----------> x=660/5-----> x=132 hertz
the answer Part b) is
132 hertz</span>
1. Start by identifying what the question wants so we are looking for miles per 1 gallon.
2. Set up a statement. When the word “per” is being used it relates to a fraction or a ratio. In this question we need to find how many miles a single gallon will give us. So set it up as miles/gallons
3. Plug in your numbers. Now our statement is 13 miles/15 gallons
4. Calculate. So do 13/15 which equals 0.86 miles per 1 gallon.
Tip: always add in words into your calculations. Mainly the units you are using so you can quickly look and know what the units will be. This will help you in upper placement math as well
