Answer:
54
Step-by-step explanation:
The complete question is
"Find the general solution of the given differential equation
y''-y=0, y1(t)=e^t , y2(t)=cosht
The function
is the solution of the given differential equation.
The function y(t)=cosht is the solution of given differential equation.
<h3>What is a function?</h3>
The function is a type of relation, or rule, that maps one input to specific single output.
Given;

Given differential equations are,
y''-y = 0
So that,
Substitute values in the given differential equation.

Therefore, the function
is the solution of the given differential equation.
Another function;
So that,

Hence, function y(t)=cosht is solution of given differential equation.
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Answer:
128
Step-by-step explanation:
180 - 52
Missing term = –2xy
Solution:
Let us first find the quotient of
.


Taking common term xy outside in the numerator.

Both xy in the numerator and denominator are cancelled.

Thus, the quotient of
is
.
Given the quotient of
is same as the product of 4xy and ____.
× missing term
Divide both sides by 4xy, we get
⇒ missing term = 
Cancel the common terms in both numerator and denominator.
⇒ missing term = –2xy
Hence the missing term of the product is –2xy.
The graph of the given system of linear inequalities
y < -1/2 + 2
y > -3/2x + 2
is attached below
<h3>Graph of system of linear inequalities </h3>
From the given information, we are to graph the given system of linear inequalities
The given system of linear inequalities is
y < -1/2 + 2
y > -3/2x + 2
The graph of the given system of linear inequalities
y < -1/2 + 2
y > -3/2x + 2
is shown below
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