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3 years ago

Solve for P I am so confused

Mathematics

2 answers:

vova2212 [387]3 years ago

8 0

Answer:

$\large\boxed{p=-\dfrac{3}{2}q}$

Step-by-step explanation:

$3(p+q)=p\qquad\text{use the distributive property:}\ a(b+c)=ab+ac\\\\3p+3q=p\qquad\text{subtract}\ 3q\ \text{from both sides}\\\\3p+3q-3q=p-3q\\\\3p=p-3q\qquad\text{subtract}\ p\ \text{from both sides}\\\\3p-p=p-p-3q\\\\2p=-3q\qquad\text{divide both sides by 2}\\\\\dfrac{2p}{2}=\dfrac{-3q}{2}\\\\\boxed{p=-\dfrac{3}{2}q}$

Jlenok [28]3 years ago

4 0

Answer:

3q/2

Step-by-step explanation:

3p+3q=p

2p=-3q

p=-3q/2

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There are three children’s in Kadri family.the sum of their ages is 15 the product of their age is 80 how old are each of the ka

sasho [114]

Answer:

8, 5, and 2

Step-by-step explanation:

8+5+2= 15

8 x 5 x 2 = 80

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3 years ago

Darsh’s simulated samples:

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Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

The angle of elevation from a buoy in the water to the top of a lighthouse is 68degrees. If a buoy is 300 ft from the base of th

Katen [24]

Answer:

The height of the lighthouse is $742.5\ ft$

Step-by-step explanation:

Let

h -----> the height of the lighthouse

we know that

The tangent of angle of 68 degrees is equal to divide the height of the lighthouse by the horizontal distance from the buoy to the base of lighthouse

$tan(68\°)=\frac{h}{300}$

Solve for h

$h=(300)tan(68\°)=742.5\ ft$

7 0

3 years ago

The 5th term in a geometric sequence is 160. The 7th term is 40. What are possible values of the 6th term of the sequence?

omeli [17]

Answer:

C. The 6th term is positive/negative 80

Step-by-step explanation:

Given

Geometric Progression

$T_5 = 160$

$T_7 = 40$

Required

$T_6$

To get the 6th term of the progression, first we need to solve for the first term and the common ratio of the progression;

To solve the common ratio;

Divide the 7th term by the 5th term; This gives

$\frac{T_7}{T_5} = \frac{40}{160}$

Divide the numerator and the denominator of the fraction by 40

$\frac{T_7}{T_5} = \frac{1}{4}$ ----- equation 1

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Where n is the nth term

So,

$T_7 = a r^{6}$

$T_5 = a r^{4}$

Substitute the above expression in equation 1

$\frac{T_7}{T_5} = \frac{1}{4}$ becomes

$\frac{ar^6}{ar^4} = \frac{1}{4}$

$r^2 = \frac{1}{4}$

Square root both sides

$r = \sqrt{\frac{1}{4}}$

r = ± $\frac{1}{2}$

Next, is to solve for the first term;

Using $T_5 = a r^{4}$

By substituting 160 for T5 and ± $\frac{1}{2}$ for r;

We get

$160 = a \frac{1}{2}^{4}$

$160 = a \frac{1}{16}$

Multiply through by 16

$16 * 160 = a \frac{1}{16} * 16$

$16 * 160 = a$

$2560 = a$

Now, we can easily solve for the 6th term

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Here, n = 6;

$T_6 = a r^{6-1}$

$T_6 = a r^5$

$T_6 = 2560 r^5$

r = ± $\frac{1}{2}$

So,

$T_6 = 2560( \frac{1}{2}^5)$ or $T_6 = 2560( \frac{-1}{2}^5)$

$T_6 = 2560( \frac{1}{32})$ or $T_6 = 2560( \frac{-1}{32})$

$T_6 = 80$ or $T_6 = -80$

$T_6 =$ ±80

Hence, the 6th term is positive/negative 80

8 0

3 years ago

Which transformation moves all points the same distance in the same direction?

Lesechka [4]

Answer:

In a translation, ALL of the points move the same distance in the same direction. A translation is called a rigid transformation or isometry because the image is the same size and shape as the pre-image.

Step-by-step explanation:

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3 years ago