The axis of symmetry of a parabola is a vertical line that divides the parabola into two congruent halves. The axis of symmetry always passes through the vertex of the parabola<span>. We determine as follows:
y = 2x^2 - 4x + 1
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y = a(x – h)2<span> + k
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y = 2(x^2 - 2x) + 1
y = 2(x^2 - 2x + 1) + 1 - 1
y = 2(x - 1)^2
Therefore, the line of symmetry passes through the vertex ( 1, 0) with an equation x = 1.