2cos(x) - 4sin(x) = 3
use identity [cos(x)]^2 +[ sin(x)]^2 = 1 => cos(x) = √[1 - (sin(x))^2]
2√[1 - (sin(x))^2] - 4 sin(x) = 3
2√[1 - (sin(x))^2] = 3 + 4 sin(x)
square both sides
4[1 - (sin(x))^2] = 9 + 24 sin(x) + 16 (sin(x))^2
expand, reagrup and add like terms
4 - 4[sin(x)]^2 = 9 + 24sin(x) + 16sin^2(x)
20[sin(x)]^2 + 24sin(x) +5 = 0
use quadratic formula and you get sin(x) = -0.93166 and sin(x) = -0.26834
Now use the inverse functions to find x:
arcsin(-0.93166) = 76.33 degrees
arcsin(-0.26834) = 17.30 degrees
Answer:
60º
Step-by-step explanation:
Label the radii OB and OC where AB and AC are tangents. OB and OC are 4.5 cm as they are both radii. Then we can see that OBA and OCA are both right triangles with OBA=OCA=90º. OAB=OAC=30º because the side lengths fit the criteria for a 30-60-90 triangle. OAB+OAC=60º
Answer:
y = -3x + 1
Step-by-step explanation:
hope this is right!
Answer:
could you maybe give me a better picture in the light or something? it is hard for me to see it
Step-by-step explanation: