Question

What is the solution to the equation 1/square root of 8 = 4^(m + 2)?

Answer 1

Take the log (base 4) of both sides of the equation.
$\log_{4}(\frac{1}{\sqrt{8}}) = m + 2$
$\frac{-1}{2} \log_{4}(4^{\frac{3}{2}})-2 = m$
$-2 \frac{3}{4}= m$

The appropriate choice is ...
  m = -11/4

Answer 2

I agree with the other person, the answer is -11/4