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IgorC [24]
3 years ago
14

What is not a whole number

Mathematics
2 answers:
Nady [450]3 years ago
7 0

Answer:

-1, -2, -0.5 etc.

Step-by-step explanation:

melomori [17]3 years ago
4 0

any number contained a decimal, or a fraction such as 1/5, 3/4, etc.

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How many cubes with a side length of 3 cm can be placed inside a box with length of 18 cm, width of 6 cm and height of 9 cm?
vodka [1.7K]

Answer:

36 cubes.

Step-by-step explanation:

to find the number of cubes:

first, identify the volume of the box using the formula: LxWxH

18cm x 6cm x 9cm = 972 cm³

next, identify the volume of the cube to be placed:

given: cube with a side length of 3 cm

Thus, volume of the cube is 3³=27cm³

To identify the number of cubes, divide the volume of the box to the volume of the cubes. 972/27 = 36. Thus we need 36 cubes.

7 0
4 years ago
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When you write a repeating decimal, how do you decide where to draw the bar?
Dmitriy789 [7]
You put the bar over the first number after the decimal
8 0
3 years ago
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Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth -5y^2+2y=-2
77julia77 [94]
5y^2-2y-2 = 0

y = 1/5+ √11/5 or 1/5 - √11/5
6 0
3 years ago
Sam purchased 2 pairs of sneakers for $225 in
PilotLPTM [1.2K]

Answer:

173.25

173.25+7=

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Step-by-step explanation:

5 0
3 years ago
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What are the roots of 4x^2 + 176 = 0?
marin [14]
Roots are the same as zeros, and you find them by factoring and solving for y.  This one is easiest if done by "taking roots" method.  Let's move the 176 over to the other side and then divide both sides by 4 to get the x^2 alone.  If we do that have we get x^2 = -44.  But we know that we cannot take the square root of a negative number without accounting for it by using the imaginary "i".  Since "i" is equal to -1, let's rewrite that [sqrt-44] as [sqrt(-1)(44)].  Now let's simplify the 44 by finding its perfect square hidden in there: [sqrt(-1)(4)(11)].  Now, because -1 = i^2, we can rewrite that as well like this:
[sqrt(i^2)(4)(11)].  Both the i^2 and the 4 are perfect squares so that's what we pull out, leaving the 11 inside for an answer of x = +/- 2i[sqrt(11)]
4 0
4 years ago
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