Answer:
probability that the other side is colored black if the upper side of the chosen card is colored red = 1/3
Step-by-step explanation:
First of all;
Let B1 be the event that the card with two red sides is selected
Let B2 be the event that the
card with two black sides is selected
Let B3 be the event that the card with one red side and one black side is
selected
Let A be the event that the upper side of the selected card (when put down on the ground)
is red.
Now, from the question;
P(B3) = ⅓
P(A|B3) = ½
P(B1) = ⅓
P(A|B1) = 1
P(B2) = ⅓
P(A|B2)) = 0
(P(B3) = ⅓
P(A|B3) = ½
Now, we want to find the probability that the other side is colored black if the upper side of the chosen card is colored red. This probability is; P(B3|A). Thus, from the Bayes’ formula, it follows that;
P(B3|A) = [P(B3)•P(A|B3)]/[(P(B1)•P(A|B1)) + (P(B2)•P(A|B2)) + (P(B3)•P(A|B3))]
Thus;
P(B3|A) = [⅓×½]/[(⅓×1) + (⅓•0) + (⅓×½)]
P(B3|A) = (1/6)/(⅓ + 0 + 1/6)
P(B3|A) = (1/6)/(1/2)
P(B3|A) = 1/3
16 gal... 480 mi
1 gal... 480/16 = 30 mi
9 gal.. 30*9 = 270 mi
<h3><u>The value of x is equal to 1.</u></h3><h3><u>6(x + 2) = 20x - 2</u></h3>
<em><u>Distributive property.</u></em>
6x + 12 = 20x - 2
<em><u>Add 2 to both sides.</u></em>
6x + 14 = 20x
<em><u>Subtract 16x from both sides.</u></em>
14 = 14x
<em><u>Divide both sides by x.</u></em>
x = 1
Answer:
is number 6
Step-by-step explanation:
the greatest common factor is the largest common factor of those.
