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Kitty [74]
3 years ago
7

The degree measure of an angle in a right triangle is x, and sin x = 1/3 . Which of these expressions are also equal to 1/3 ? Se

lect all that apply. A) cos(x) b) cos(x - 45°) c) cos(45° - x) d) cos (60° - x ) e) cos(90° - x)
EXPLAIN!!!!
Mathematics
1 answer:
Novosadov [1.4K]3 years ago
3 0

Answer:

e) cos(90° - x)

Step-by-step explanation:

we know that

If two angles are complementary, the cofunction identities state that the sine of one equals the cosine of the other and vice versa

The complementary angle of angle x is equal to (90-x) degrees

therefore

sin(x^o)=cos(90-x)^o

You might be interested in
Triangle DEF is a right triangle. Angle F is a right angle and m∠E=29°.<br><br> What is m∠D?
Aleksandr-060686 [28]

All triangles have 180o in them when the 3 angles making them up are added together.


Givens

F = 90

E = 29

D = ???


Equation

<D + <E + <F = 180


Substitute and solve

<D + 90 + 29 = 180

<D + 119 = 180

<D = 180 - 119

<D = 61

5 0
3 years ago
Read 2 more answers
Everything is in the picture PLEASE HELP me ASAP and I'll give you the BRAINLIEST PLS IM BEGGING ​
anygoal [31]

Answer:

21.5cm²

Step-by-step explanation:

First you find out the Area of the square itself which is 100cm² (squared). Then you Find the Area of the circle. The formula to find the area of a circle is  π  × Radius². So you find the diameter of the circle (which is 10) and divide that by 2 to find the radius. So the radius is 5 but then you need to square 5 which is 25. Then you multiply 25 with pi which is 78.5 so the area of the circle is 78.5cm². Now what you have to do is subtract the area of the square and the area of the circle to find the area of the shaded region. 100-78.5 is 21.5cm ² and that is the answer.

4 0
3 years ago
I NEED HELP WITH THIS ASAP <br> I WILL GIVE BRAINLIEST
natita [175]

Answer

x=100

y= 4.5

x=6

y= 1.87

Step-by-step explanation:

4 0
3 years ago
Consider the following pair of equations:
Mariana [72]
Hellooo..
my answer is (-4,2)

8 0
3 years ago
Una caja de 25 newtons se suspende mediante un cable con diámetro de 2cm¿cuál es el esfuerzo aplicado al cable?
Naddik [55]

El cable experimenta un esfuerzo axial de 79577.472 pascales por el peso de la caja.

<h3>¿Cómo calcular el esfuerzo aplicado sobre el cable?</h3>

La caja tiene masa y está sometida a un campo gravitacional, por tanto, tiene un peso (W), en newtons. Por el principio de acción y reacción (tercera ley de Newton), encontramos que el cable es tensionado debido a ese peso y su área transversal experimenta un esfuerzo axial (σ), en pascales.

Asumiendo una distribución uniforme de la fuerza sobre toda la superficie transversal de la cuerda, tenemos que el esfuerzo axial se calcula mediante la siguiente expresión:

σ = W / (π · D² / 4)

Donde:

  • W - Peso de la caja, en newtons.
  • D - Diámetro del área transversal de la caja, en metros.

Si sabemos que W = 25 N y D = 0.02 m, entonces el esfuerzo axial aplicado a la cuerda es:

σ = 25 N / [π · (0.02 m)² / 4]

σ ≈ 79577.472 Pa

<h3>Observación</h3>

La falta de problemas verificados en español sobre esfuerzos axiales obliga a buscar uno equivalente en inglés.

Para aprender más sobre esfuerzos axiales: brainly.com/question/13683145

#SPJ1

5 0
1 year ago
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