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xeze [42]
3 years ago
7

Zoe and Hannah share tips in the ratio 3:7 Last week ,Zoe received £24

Mathematics
1 answer:
kakasveta [241]3 years ago
7 0

Hannah received  24 * 7 / 3 =  £56

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A rectangle has a width of 9 units and a length of 40 units. What is the length of a diagonal? 31 units 39 units 41 units 49 uni
BigorU [14]

Answer:

41

Step-by-step explanation:

So basically you need to use the pythagorean thrm. Essentially, the diagonal and the width and length create a triangle, the diagonal being the hypothenuse. So the formula goes as \sqrt[]{a^{2} +b^{2} }. the variable "a" being the length and the variable "b" being the width.  So plug it in and there you have your answer!

8 0
3 years ago
Hi guys how is your day going?
Dafna11 [192]

Answer:

good u?

Step-by-step explanation:

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3 years ago
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hodyreva [135]
It would be 14 for the perimeter
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2 years ago
What is the average rate of change for this function for the interval from x=3 to x=5?​
timofeeve [1]

Answer:

B

Step-by-step explanation:

The average rate of change of f(x) in the closed interval [ a, b ] is

\frac{f(b)-f(a)}{b-a}

Here [ a, b ] = [ 3, 5 ]

From the table of values

f(b) = f(5) = 32

f(a) = f(3) = 8

Hence

average rate of change = \frac{32-8}{5-3} = \frac{24}{2} = 12

4 0
3 years ago
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the first group of students consists of 10 and their average age was 13 years old the next group consisted of 30 students and th
Kazeer [188]

Answer: The average was 9 years old find the average age of both groups is 10 years old.

Step-by-step explanation:

Formula foe average : \text{Average} =\dfrac{\text{Sum of all observations}}{\text{Number of observations}}

Given : The first group of students consists of 10 and their average age was 13 years old.

i.e. 13=\dfrac{\text{Sum of ages of students of first group}}{10}\\\\\Rightarrow\ \text{Sum of ages of students of first group}=13\times10=130      (1)

The next group consisted of 30 students and their average was 9 years old.

i.e. 9=\dfrac{\text{Sum of ages of students of next group}}{30}\\\\\Rightarrow\ \text{Sum of ages of students of nextgroup}=9\times30=270      (2)

Then from (1) and (2) , the sum of both groups (first group and next group )students = 130+270 =400

Combined students of both groups (first and next group )= 10+30=40

Now , the average of both groups =\dfrac{\text{Sum of combined students}}{\text{combined students}}

=\dfrac{400}{40}=10

Hence, the average was 9 years old find the average age of both groups is 10 years old.

4 0
3 years ago
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