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Licemer1 [7]
3 years ago
10

An equation contains at least one variable

Mathematics
2 answers:
Olin [163]3 years ago
8 0

Answer:

x+2=5

x+3=6

x^2 + 3x + 2 = 0

There are infinetly many equations that contain at least one variable!

Step-by-step explanation:

Umnica [9.8K]3 years ago
5 0
It’s true that a equation at least contains one variable
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Jason tossed a fair coin 3 times. What is the probability of getting a head and two tails in any order 1.3/8 2.4/8 3.5/8 4.6/8 p
ladessa [460]

Answer:

1. 3/8

Step-by-step explanation:

Total tossed times = 3

Total Possibilities = 8

Possibilities = (Head, Head, Head), (Tails,Tail,Tails), (Head,Head,Tails), (Head,Tail,Head), (Tails,Head,Head), (Head,Tail,Tail), (Tail,Tail,Head), (Tail,Head,Tail)

Number of options with a head and two tails = 3

So, Probability = Number of correct options ÷ Number of total possibilities

= 3 ÷ 8 or 3/8

4 0
3 years ago
Solve the equation. e² = 0.36
REY [17]
E^2=0.36  take the square root of both sides

e=±0.6
6 0
3 years ago
Find the slope given the points (2, −7) and (−1,<br> 6).
lesya [120]

Answer:

The Slope= -13/3

y-intercept= (0,5/3)

Step-by-step explanation:

m= change in y/change in x

m= y2-y1/x2-x1

m=6-(-7)/ -1-(2)

m=-13/3

4 0
2 years ago
5. The recursive algorithm given below can be used to compute gcd(a, b) where a and b are non-negative integer, not both zero.
s2008m [1.1K]

Implementating the given algorithm in python 3, the greatest common divisors of <em>(</em><em>124</em><em> </em><em>and</em><em> </em><em>244</em><em>)</em><em> </em>and <em>(</em><em>4424</em><em> </em><em>and</em><em> </em><em>2111</em><em>)</em><em> </em>are 4 and 1 respectively.

The program implementation is given below and the output of the sample run is attached.

def gcd(a, b):

<em>#initialize</em><em> </em><em>a</em><em> </em><em>function</em><em> </em><em>named</em><em> </em><em>gcd</em><em> </em><em>which</em><em> </em><em>takes</em><em> </em><em>in</em><em> </em><em>two</em><em> </em><em>parameters</em><em> </em>

if a>b:

<em>#checks</em><em> </em><em>if</em><em> </em><em>a</em><em> </em><em>is</em><em> </em><em>greater</em><em> </em><em>than</em><em> </em><em>b</em>

return gcd (b, a)

<em>#if</em><em> </em><em>true</em><em> </em><em>interchange</em><em> </em><em>the</em><em> </em><em>Parameters</em><em> </em><em>and</em><em> </em><em>Recall</em><em> </em><em>the</em><em> </em><em>function</em><em> </em>

elif a == 0:

return b

elif a == 1:

return 1

elif((a%2 == 0)and(b%2==0)):

<em>#even</em><em> </em><em>numbers</em><em> </em><em>leave</em><em> </em><em>no</em><em> </em><em>remainder</em><em> </em><em>when</em><em> </em><em>divided</em><em> </em><em>by</em><em> </em><em>2</em><em>,</em><em> </em><em>checks</em><em> </em><em>if</em><em> </em><em>a</em><em> </em><em>and</em><em> </em><em>b</em><em> </em><em>are</em><em> </em><em>even</em><em> </em>

return 2 * gcd(a/2, b/2)

elif((a%2 !=0) and (b%2==0)):

<em>#checks</em><em> </em><em>if</em><em> </em><em>a</em><em> </em><em>is</em><em> </em><em>odd</em><em> </em><em>and</em><em> </em><em>B</em><em> </em><em>is</em><em> </em><em>even</em><em> </em>

return gcd(a, b/2)

else :

return gcd(a, b-a)

<em>#since</em><em> </em><em>it's</em><em> </em><em>a</em><em> </em><em>recursive</em><em> </em><em>function</em><em>,</em><em> </em><em>it</em><em> </em><em>recalls</em><em> </em><em>the function</em><em> </em><em>with </em><em>new</em><em> </em><em>parameters</em><em> </em><em>until</em><em> </em><em>a</em><em> </em><em>certain</em><em> </em><em>condition</em><em> </em><em>is</em><em> </em><em>satisfied</em><em> </em>

print(gcd(124, 244))

print()

<em>#leaves</em><em> </em><em>a</em><em> </em><em>space</em><em> </em><em>after</em><em> </em><em>the</em><em> </em><em>first</em><em> </em><em>output</em><em> </em>

print(gcd(4424, 2111))

Learn more :brainly.com/question/25506437

6 0
2 years ago
The square of even numbers are even number .show?​
natima [27]

Answer:

. It’s because a prime factor of all even numbers is 2. Therefore the prime factors of all even squares includes two, therefore, the square must be even.

3 0
3 years ago
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