Answer:
E(X) = 6
Var(X) = 3.394
Step-by-step explanation:
Let X represent the number of carp caught out of the 20 fishes caught. Now, if we are to assume that each
of the (100, 20) ways to catch the 20 fishes will be equally likely.
Thus, we can say that X fulfills a hypergeometric
distribution with parameters as follows;
n = 20, N = 100, k = 30
Formula for expected mean value in hypergeometric distribution is;
E(X) = nk/N
E(X) = (20 × 30)/100
E(X) = 6
Formula for variance is;
Var(X) = (nk/N) × [((n - 1)(k - 1)/(N-1))) + (1 - nk/N)]
Var(X) = ((20 × 30)/100) × [((20 - 1)(30 - 1)/(100 - 1)) + (1 - (20 × 30/100)]
Var(X) = 6 × 0.5657
Var(X) = 3.394
I don’t know what the answer is I wish I could help
It would be 8:5.
Ratios are very simple. There're basically just writing one number per the other number, exept instead of writing per, you write : or /.
Hiya!
First, you can plot this using a table. One side can be 'Women' and the other 'Men'. One the vertical side of it, write '1980', '1981', '1982', etc., for maybe fifteen years to be on the safe side. Then, your starting value is 6 million and 5.4 million, respectively.
Finally, start adding up! It will be, 6.14 million, 6.28 million, etc., and 5.4 million, 5.48 million, etc.
Once you're done, you can circle the year both were the same, and you can even plot this on a graph to prove to your teacher you know what's business! ;)
If you found this especially helpful, I'd appreciate if you'd vote me Brainliest for your answer. I want to be able to assist more users one-on-one! :)
Answer:
No
Step-by-step explanation:
The triangles are not similar because line KM and GM are similar, and angle M are similar, but HM and JM are not.