Problem 2
Plot point L anywhere that isn't on segment JK. Draw a line through point L. I find it helps to make the lines parallel.
Next, use a compass to measure the width of segment JK. Keeping this same width, transfer the nonpencil end of the compass to point L. Draw an arc that crosses the line through L.
Mark this intersection point M. Lastly, use a pen or marker to form segment LM and erase everything else of that line.
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Problem 3
The ideas of the previous problem will be used here. We copied segment JK to form congruent segment LM. So JK = LM.
The same steps will be used to form segment GN where GN = EF. In other words, segment GN is a perfect copy of segment EF.
If you repeat these steps again, you'll get another segment of the same length. This segment goes from point N to point H. So NH = GN = EF
Then we can say,
GH = GN + NH
GH = EF + EF
GH = 2*EF
Answer:
101 is your answer
Step-by-step explanation:
Remember to follow PEMDAS & the left->right rule.
First, multiply 12 with 13:
12 x 13 = 156
Next, divide 156 with 2
156/2 = 78
Finally, add 23
78 + 23 = 101
101 is your answer
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Answer:
B
Step-by-step explanation:
the supplement is the angle that will add to the other angle to get 180 degrees. 180-129=51 which is B.
Find the area of the circle then, multiply that by the height of the cylinder.
Area of a circle = PI x r^2
Area = PI x 8^2 = 64PI
Volume = 64PI x 11 = 704PI in^3
Answer:
125
Step-by-step explanation:
anything that is above .5 will round up and below .4 will round down.
