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3 years ago

At a football game, a vender sold a combined total of 201

Mathematics

1 answer:

gizmo_the_mogwai [7]3 years ago

5 0

We know that soda + hot dog =201

soda is 2x

hot dog is x

2x+x=201

3x=201

divide each side by 3

x=67

2x=134

They sold 134 sodas and 67 hotdogs

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Khloe drove 204 miles in 4 hours. If she continued at the same rate, how long would

Minchanka [31]

Answer:

15 hrs.

Step-by-step explanation:

204/4 = 51 miles per hrour

765/51 = 15 hrs.

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3 years ago

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April worked 1 1/2 times as long on her math project as did Carl. Debbie worked 1 1/4 times as long as Sonia. Richard worked 1 3

vlada-n [284]

Answer:

Student Hours worked

April. $7\frac{7}{8} \ hrs$

Debbie. $8\frac{1}{8}\ hrs$

Richard. $7\frac{19}{24}\ hrs$

Step-by-step explanation:

Some data's were missing so we have attached the complete information in the attachment.

Given:

Number of Hours Carl worked on Math project = $5\frac{1}{4}\ hrs$

$5\frac{1}{4}\ hrs$ can be Rewritten as $\frac{21}{4}\ hrs$

Number of Hours Carl worked on Math project = $\frac{21}{4}\ hrs$

Number of Hours Sonia worked on Math project = $6\frac{1}{2}\ hrs$

$6\frac{1}{2}\ hrs$ can be rewritten as $\frac{13}{2}\ hrs$

Number of Hours Sonia worked on Math project = $\frac{13}{2}\ hrs$

Number of Hours Tony worked on Math project = $5\frac{2}{3}\ hrs$

$5\frac{2}{3}\ hrs$ can be rewritten as $\frac{17}{3}\ hrs.$

Number of Hours Tony worked on Math project = $\frac{17}{3}\ hrs.$

Now Given:

April worked $1\frac{1}{2}$ times as long on her math project as did Carl.

$1\frac{1}{2}$ can be Rewritten as $\frac{3}{2}$

Number of Hours April worked on math project = $\frac{3}{2}$ $\times$ Number of Hours Carl worked on Math project

Number of Hours April worked on math project = $\frac{3}{2}\times \frac{21}{4} = \frac{63}{8}\ hrs \ \ Or \ \ 7\frac{7}{8} \ hrs$

Also Given:

Debbie worked $1\frac{1}{4}$ times as long as Sonia.

$1\frac{1}{4}$ can be Rewritten as $\frac{5}{4}$ .

Number of Hours Debbie worked on math project = $\frac{5}{4}$ $\times$ Number of Hours Sonia worked on Math project

Number of Hours Debbie worked on math project = $\frac{5}{4}\times \frac{13}{2}= \frac{65}{8}\ hrs \ \ Or \ \ 8\frac{1}{8}\ hrs$

Also Given:

Richard worked $1\frac{3}{8}$ times as long as tony.

$1\frac{3}{8}$ can be Rewritten as $\frac{11}{8}$

Number of Hours Richard worked on math project = $\frac{11}{8}$ $\times$ Number of Hours Tony worked on Math project

Number of Hours Debbie worked on math project = $\frac{11}{8}\times \frac{17}{3}= \frac{187}{24}\ hrs \ \ Or \ \ 7\frac{19}{24}\ hrs$

Hence We will match each student with number of hours she worked.

Student Hours worked

April. $7\frac{7}{8} \ hrs$

Debbie. $8\frac{1}{8}\ hrs$

Richard. $7\frac{19}{24}\ hrs$

5 0

3 years ago

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Simplify the following expression.<br> 2x + 3x3 - 5x2 + x2 +7x + 1+ 7x -3x3 - 4

denis-greek [22]

-4x^2+16x-3 is your answer

8 0

3 years ago

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The cable company takes an SRS of 250 of the approximately 15,000 households who subscribe to them. They found that 75 percent o

kati45 [8]

Answer:

Answer; Mean = p = 0.75

Standard deviation =0.0274

Step-by-step explanation:

Mean = p = 0.75

Standard deviation = √ [ p ( 1 - p) / n ]

= √ [ 0.75 * ( 1 - 0.75) / 250]

= 0.0274

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3 years ago

A square base of a pyramid has the dimensions 5 yards

AfilCa [17]

Answer:

145 yd²

Step-by-step explanation:

There will be dour triangular faces. For a triangle, area is given as

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Since they are four similar triangles, area of triangular faces will be 30*4=120 yd²

The surface area of a square base is given by

A=a*a=a² where a is the dimension of one side. Given that the meaurement is 5 yards then A=5²=25 yd²

Total area will be the sum of triangular and square faces hence 120+25=145 yd²

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4 years ago

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