All categories

3 years ago

Write down in terms of N and expression for the nth term of the following sequence 25 20 15 10 5

Mathematics

1 answer:

GREYUIT [131]3 years ago

8 0

Answer:

30x-5

Step-by-step explanation:

25-5=20

20-5=15

-5 -10 -15 -20 -25

25 20 15 10 5

I hope that helped you

You might be interested in

18=w over 2<br><br> Please help and explain!

dusya [7]

W is the variable.So try figuring out what the variable (W) represent and the value

3 0

3 years ago

Read 2 more answers

A clock was set on Monday at 8.30 a.m. On Tuesday, the following day, the clock showed 8.45 p.m. when the correct time was 8.30

lilavasa [31]

Step-by-step explanation:

It gained 15 minutes in 36 hours.

15/36 = x/24

36x = 360

x = 10 minutes

8 0

2 years ago

Help me pleaseeeeeeeeeeeee

ratelena [41]

The answer is A
r = 1

5 0

3 years ago

Read 2 more answers

I Dont understand what to do

Sati [7]

You need to find the area of this

4 0

3 years ago

Use Lagrange multipliers to find the maximum and minimum values of

marusya05 [52]

The Lagrangian is

$L(x,y,\lambda)=x+8y+\lambda(x^2+y^2-4)$

It has critical points where the first order derivatives vanish:

$L_x=1+2\lambda x=0\implies\lambda=-\dfrac1{2x}$

$L_y=8+2\lambda y=0\implies\lambda=-\dfrac4y$

$L_\lambda=x^2+y^2-4=0$

From the first two equations we get

$-\dfrac1{2x}=-\dfrac4y\implies y=8x$

Then

$x^2+y^2=65x^2=4\implies x=\pm\dfrac2{\sqrt{65}}\implies y=\pm\dfrac{16}{\sqrt{65}}$

At these critical points, we have

$f\left(\dfrac2{\sqrt{65}},\dfrac{16}{\sqrt{65}}\right)=2\sqrt{65}\approx16.125$ (maximum)

$f\left(-\dfrac2{\sqrt{65}},-\dfrac{16}{\sqrt{65}}\right)=-2\sqrt{65}\approx-16.125$ (minimum)

5 0

3 years ago