A bag contains 2 green, 9 brown, 7 yellow, and 4 blue marbles.
1 answer:
Step-by-step explanation:
Given data
2 green,
9 brown,
7 yellow, and
4 blue marbles.
Sample space S = 2+9+7+4= 22
The probability of picking a ball without replacement
Probability of picking each ball
Pr(green) = 2/22= 1/11
Pr(brown ) = 9/21
Pr(yellow) = 7/20
Pr(blue) = 4/19
Probability of picking yellow then another yellow
P(yellow, then yellow)
=(7/22)*(6/21)= 42/462
=1/11
A. 1/11
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