Question

Can someone help me please

Answer 1

$\displaystyle\\Answer:\ y=\frac{x}{3}-60$

Step-by-step explanation:

                                            y=kx+b    (1)

     The formula for the slope coefficient of the straight line

                               $\displaystyle\\\boxed {k=\frac{rise}{run}=\frac{y_2-y_1}{x_2-x_1} }$

Choose two coordinate points belonging to the line: (0,-60)  (30,-50)

Hence,

$\displaystyle\\k=\frac{-50-(-60)}{30-0} \\\\k=\frac{-50+60}{30}\\\\k=\frac{10}{30} \\\\k=\frac{1*10}{3*10} \\\\k=\frac{1}{3} \\\\Thus, \ y=\frac{1}{3} x+b\\(0,-60)\\-60=\frac{1}{3} (0)+b\\-60=0+b\\-60=b\\\\As \ a\ result:\\\\y=\frac{x}{3}-60$

Answer 2

Y=1/3(x+(3*(-60))) => y=1/3(x-180)