Answer: Thus the cell potential of an electrochemical cell is +0.28 V
Explanation:
The calculation of cell potential is done by :
Where both 
are standard reduction potentials.
![E^0_{[Fe^{2+}/Fe]}= -0.41V](https://tex.z-dn.net/?f=E%5E0_%7B%5BFe%5E%7B2%2B%7D%2FFe%5D%7D%3D%20-0.41V)
![E^0_{[Pb^{2+}/Pb]}=-0.13V](https://tex.z-dn.net/?f=E%5E0_%7B%5BPb%5E%7B2%2B%7D%2FPb%5D%7D%3D-0.13V)
As Reduction takes place easily if the standard reduction potential is higher(positive) and oxidation takes place easily if the standard reduction potential is less(more negative). Thus iron acts as anode and lead acts as cathode.
![E^0=E^0_{[Pb^{2+}/Pb]}- E^0_{[Fe^{2+}/Fe]}](https://tex.z-dn.net/?f=E%5E0%3DE%5E0_%7B%5BPb%5E%7B2%2B%7D%2FPb%5D%7D-%20E%5E0_%7B%5BFe%5E%7B2%2B%7D%2FFe%5D%7D)
Thus the cell potential of an electrochemical cell is +0.28 V
The three situations can be described as
a) If we have two white powders and wish to distinguish between the two : the combinations can be sugar / salt or sugar / baking soda or salt / baking soda
all are kitchen items so we can either taste them
or in case of baking soda we can add it in water and it will produce brisk effervescence.
b) IF we have to distinguish in a given set of two transparent liquids which appear to be water (example water and vinegar)
we can identify them with the taste
we can identify them based on pH (vinegar will be acidic)
c) We have to find adulteration in a given sample of food
like adulteration in milk
for example presence of soap in milk
We can add indicator like phenolphthalein which will bring a pink colour in milk if soap is present
Answer:
Yes
no
no
yes
yes
yes
no
yes
yes
no
Some of these activitise that i said yes don't nessiseraly require you to hear, rather it would affect your experiance doing them without ears or the ability to hear. You realy don't need to be able to hear to play a gauter, it depends on how you learn.
