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4 years ago

How does mass affect thermal energy transfer?

Chemistry

1 answer:

givi [52]4 years ago

8 0

If two objects have the same mass, the object with the higher temperature has greater thermal energy.

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What happens when grapes get fermented

ValentinkaMS [17]

When grapes become fermented, they turn into wine.

6 0

3 years ago

Calculate the unit cell edge length for an 78 wt% Ag- 22 wt% Pd alloy. All of the palladium is in solid solution, and the crysta

BaLLatris [955]

Answer:

The unit cell edge length for the alloy is 0.405 nm

Explanation:

Given;

concentration of Ag, $C_{Ag}$ = 78 wt%

concentration of Pd, $C_P_d$ = 22 wt%

density of Ag = 10.49 g/cm³

density of Pd = 12.02 g/cm³

atomic weight of Ag, $A_A_g$ = 107.87 g/mol

atomic weight of iron, $A_P_d$ = 106.4 g/mol

Step 1: determine the average density of the alloy

$\rho _{Avg.} = \frac{100}{\frac{C_A_g}{\rho _A_g} + \frac{C__{Pd}}{\rho _{Pd}} }$

$\rho _{Avg.} = \frac{100}{\frac{78}{10.49} + \frac{22}{12.02} } = 10.79 \ g/cm^3$

Step 2: determine the average atomic weight of the alloy

$A _{Avg.} = \frac{100}{\frac{C_v}{A _A_g} + \frac{C__{Pd}}{A _{Pd}} }$

$A _{Avg.} = \frac{100}{\frac{78}{107.87} + \frac{22}{106.4} } = 107.54 \ g/mole$

Step 3: determine unit cell volume

$V_c=\frac{nA_{avg.}}{\rho _{avg.} N_a}$

for a FCC crystal structure, there are 4 atoms per unit cell; n = 4

$V_c=\frac{4*107.54}{ 10.79*6.022*10^{23}} = 6.620*10^{-23} \ cm^3/cell$

Step 4: determine the unit cell edge length

Vc = a³

$a = V_c{^\frac{1}{3} }\\\\a = (6.620*10^{-23}}){^\frac{1}{3}}\\\\a = 4.05 *10^{-8} \ cm$ = 0.405 nm

Therefore, the unit cell edge length for the alloy is 0.405 nm

7 0

3 years ago

Refer to the following compounds.

goblinko [34]

Answer: The answer is D. This has a Carboxylic Acid group, and is acetic acid, or Ethanoic Acid.

ALWAYS LOOK for the Functional Group in question.

A. Would likely not stay in water, or at least not be acidic, for it is butane gas.

B. Is 1-propanol, and alcohols are not acidic as a rule. Certainly not in water.

C. This is an Ether. It will not give up an H+, it it not an acid.

E. This functional group is an amine, which is more “base” like, since the lone pairs of the Nitrogen atom would tend to attract a H+.

5 0

3 years ago

Calculate the value of AE for a system that loses 50 J of heat and has 150 J of work Performed on it by the surroundings.

gavmur [86]

Answer:

100 j

Explanation:

bascially u j subtract 50 from 150 because the system lost 50 j but theres 150 in its surroundings

4 0

3 years ago

How to do it???????????

amm1812

Tempratures

1. -60 C = 213.15 K

2. 250 C= 523.15 K

3. 365 K = 91.85 C

4. 205 K = -68.15 C

Pressures

1. 22.0 inches Hg = 558.8 mm Hg

2. 3.4 atm = 2584 mm Hg

3. 680 mm Hg = 0.894737 atm

4. 785 mm Hg = 104.658 kPa

Hope this helped! Please mark as brainliest! Thanks!

Although It showes I'm a begginer, I was An Ace, till my account got deleted.

My name was Sorry14.

4 0

3 years ago