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kirill115 [55]
3 years ago
8

C. rubidium sulfate

Chemistry
1 answer:
dolphi86 [110]3 years ago
3 0
I can do that which is B
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10.Stephanie observes the color of a
dlinn [17]

Answer:

physical properties

Explanation:

temperature, volume and colour are all physical properties

7 0
3 years ago
The lipid portion of a typical bilayer is about 30 Å thick. a) Calculate the minimum number of residues in an α-helix required t
Mrrafil [7]

Answer:

a) The minimum number of residues in alfa helix to span 30 Å, is 20 residues

b) The minimum number of residues in a Beta sheet to span 30 Å, is 8.6 residues.

c) Should be better if you show an image to do this question.

d) Look answer below.

Explanation:

a) Due to every 5,4 Å there are 3,6 residues. So doing the calculus give us 20 residues.

b)  That’s it because every 7 Å there are 2 residues

c) First of all, is important to know that the residues of a protein define the secondary structure due to intermolecular and intramolecular interactions. Taking in account that the membrane bilayer has a lipid interior α-helical domains which are hydrophobic principally are embedded in membranes by hydrophobic interactions with the lipid interior of the bilayer favored by Van der Waals interactions and probably also by ionic interactions with the polar head groups of the phospholipids.

3 0
4 years ago
If 27.3% of a sample of silver-112 decays in 1.52 hours, what is the half-life (in hours to 3 decimal places)?
ICE Princess25 [194]

<u>Answer:</u> The half life of the sample of silver-112 is 3.303 hours.

<u>Explanation:</u>

All radioactive decay processes undergoes first order reaction.

To calculate the rate constant for first order reaction, we use the integrated rate law equation for first order, which is:

k=\frac{2.303}{t}\log \frac{[A_o]}{[A]}

where,

k = rate constant = ?

t = time taken = 1.52 hrs

[A_o] = Initial concentration of reactant = 100 g

[A] = Concentration of reactant left after time 't' = [100 - 27.3] = 72.7 g

Putting values in above equation, we get:

k=\frac{2.303}{1.52hrs}\log \frac{100}{72.7}\\\\k= 0.2098hr^{-1}

To calculate the half life period of first order reaction, we use the equation:

t_{1/2}=\frac{0.693}{k}

where,

t_{1/2} = half life period of first order reaction = ?

k = rate constant = 0.2098hr^{-1}

Putting values in above equation, we get:

t_{1/2}=\frac{0.693}{0.2098hr^{-1}}\\\\t_{1/2}=3.303hrs

Hence, the half life of the sample of silver-112 is 3.303 hours.

6 0
3 years ago
How many liters are equivalent to 645 mililiters
abruzzese [7]

Answer:

0.645 liters

Explanation:

THE QUESTION IS equivalent 0.645 Liters

6 0
4 years ago
Read 2 more answers
Identify the parts of the energy diagram
Aliun [14]
On the first graph the beginning flat line is the reaction. Then comes the hill will it be call the activation energy. The final flat line would be the produce. Same names apply to the 2 graph too
7 0
3 years ago
Read 2 more answers
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