Answer:
1. RbOH(s) ⇒ Rb⁺(aq) + OH⁻(aq)
2. Na₂CO₃(s) ⇒ 2 Na⁺(aq) + CO₃²⁻(aq)
3. (NH₄)₂SeO₃(s) ⇒2 NH₄⁺(aq) + SeO₃²⁻(aq)
Explanation:
Let's consider the dissolving equations for the following compounds.
1. Rubidium hydroxide
RbOH(s) ⇒ Rb⁺(aq) + OH⁻(aq)
2. Sodium carbonate
Na₂CO₃(s) ⇒ 2 Na⁺(aq) + CO₃²⁻(aq)
3. Ammonium selenite
(NH₄)₂SeO₃(s) ⇒2 NH₄⁺(aq) + SeO₃²⁻(aq)
Due to the ideal gas law, we have an equation: PV=nRT. So when the pressure and amount of gas are constant, V1/T1=V2/T2. Temperature using the unit of K. So the answer is 535*319/296=576.6 mL.
Saccharides are carbohydrates, molecules containing Carbon (C), Hydrogen (H), and Oxygen (O). "Saccharo" means sugar in Greek. Also Greek, "mono" means one, "di" means two, and "poly" means many.
A sugar molecule is based upon a ring of carbons with H's and OH's attached. One sugar molecule alone is a monosacchararide, like glucose and fructose. Two sugar molecules bonded together covalently is a disaccharide, like lactose (milk sugar) and sucrose (table sugar). Many sugar molecules (upwards of hundreds or thousands) bonded together covalently is a polysaccharide. Examples are glycogen (animal starch) and cellulose (plant starch).
Answer:
75000 Hz
Explanation:
f = V / λ (f= frequency, v=velocity of wave, lambda= wavelength)
alternatively, f = c / λ (f= frequency, c= speed of light- 3.00x10^8 m/s, lambda= wavelength)
f= [3.00x10^8 m/s]/[4000 m]
=75000 Hz
