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Helen [10]
2 years ago
5

Differentiating Functions of Other Bases In Exercise, find the derivative of the function.

Mathematics
1 answer:
zimovet [89]2 years ago
6 0

Answer:

y' = -\frac{1}{2.3x}

Step-by-step explanation:

The derivative of a*x^{n} is a*n*x^{n-1}. The derivative of 3x^{-1} is -3x^{-2}, for example.

Derivative of the log function:

y = \log_{a}{f(x)}

Has the following derivative

y' = \frac{f'(x)}{\ln{a}*f(x)}

In this problem, we have that:

y = \log_{10}{\frac{3}{x}}

So

a = 10, f(x) = \frac{3}{x} = 3x^{-1}, f'(x) = -3x^{-2}

The derivative of the function is:

y' = \frac{f'(x)}{\ln{a}*f(x)}

y' = \frac{-3x^{-2}}{2.3*3x^{-1}}

y' = -\frac{1}{2.3x}

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The correct answer is b) four.

Step-by-step explanation:

Evan and Eileen Carter must submit a separate statement as dictated by the requirements for the claim.

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The couple also provides support in all expenses of Evan's                    great-grandmother; although Belinda lives in an asylum, the Carter can claim the exemption since, for qualified relatives, they do not ask as a mandatory requirement that they live in the same place.

And finally, Peggy cannot request an exemption since she is not a qualified relative, so she does not fall within the exceptions to claim, even if she lives in Evan and Eileen Carter´s house.

Therefore, the Carter can claim four dependency exemptions, one for each person that are Evan, Eileen, Pamela, and Belinda.

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<em>I hope this information can help you.</em>

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When an object is droppednbsp on a certain earth dash like planet comma on a certain earth-like planet, the distance it falls in
ANTONII [103]

Answer:

(a) s(44) = 3.52*10^{6}ft

(b) v(44) = 10*x^{5} ft/s

(c) a(44) = 3636ft/s^{2}

Step-by-step explanation:

s(t) = 1818t^{2}

(a) when t = 44sec

s(44) = 1818(44^{2}) = 1818(1936)\\ \\s(44) = 3519648ft

s(44) ≅ 3520000=3.52*10^{6}ft

(b) How fast the hammer is traveling i.e. the speed of the hammer.

To find speed, we differentiate the distance s(t) with respect to time, t

speed,v=\frac{ds(t)}{dt}=\frac{d}{dt}(1818t^{2})   \\\\v = 1818*2t^{2-1}= 1818*2t\\ \\v = 3636t

at t = 44sec,

v = 3636*44=159984ft/s

v ≅ 160000ft/s = 1.6*10^{5}ft/s

(c) The hammer's acceleration can be obtained by differentiating the speed v(t) with respect to time, t

acceleration, a = \frac{dv}{dt}=\frac{d}{dt}(3636t)\\  \\a = 3636*1= 3636\\\\a = 3636ft/s^{2}

There's no need to substitute t = 44sec because the acceleration is independent of time.

3 0
3 years ago
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