Answer:
D
Step-by-step explanation: It's not going up by 6 or 2, and it's not going down in numbers, so D
Answer:
<em>The car will worth $15815 after 5 years.</em>
Step-by-step explanation:
The formula is:
, where P = Initial cost, A = Final cost, r = Rate of change in cost per year and t = Number of years.
Here, 
and 
As here the <u>value of the car depreciates every year, so we need to plug the value of
as negative</u>. So, 
Now plugging the above values into the formula, we will get.....

<em>(Rounded to the nearest dollar)</em>
So, the car will worth $15815 after 5 years.
Answer:
The expression that is greater is a (b - c)
Step-by-step explanation:
- a < 0 and c > b, this means <u>(by the addition property)</u> that c - c > b - c⇒0 > b - c
so for the product <u>a(b - c) </u>we would have a multiplication of a negative number <em>a</em> and another negative number <em>(b - c)</em>. We know that the result of the <u>multiplication of two negative numbers is a positive number.</u>
Therefore, a (b - c) > 0
- a < 0 and c > b, this means <u>by the addition property</u> that c - b > b - b⇒ c - b > 0
so for <u>a(c - b)</u>, we have the negative number <em>a</em> multiplied by the positive number <em>(c - b). </em>We know that the result of the <u>multiplication of a negative number by a positive number is negative. </u>
<u>Therefore a (c - b) < 0</u>
Thus, the expression that is greater is the positive one which is a (b - c)
Step-by-step explanation:
The solution to this problem is very much similar to your previous ones, already answered by Sqdancefan.
Given:
mean, mu = 3550 lbs (hope I read the first five correctly, and it's not a six)
standard deviation, sigma = 870 lbs
weights are normally distributed, and assume large samples.
Probability to be estimated between W1=2800 and W2=4500 lbs.
Solution:
We calculate Z-scores for each of the limits in order to estimate probabilities from tables.
For W1 (lower limit),
Z1=(W1-mu)/sigma = (2800 - 3550)/870 = -.862069
From tables, P(Z<Z1) = 0.194325
For W2 (upper limit):
Z2=(W2-mu)/sigma = (4500-3550)/879 = 1.091954
From tables, P(Z<Z2) = 0.862573
Therefore probability that weight is between W1 and W2 is
P( W1 < W < W2 )
= P(Z1 < Z < Z2)
= P(Z<Z2) - P(Z<Z1)
= 0.862573 - 0.194325
= 0.668248
= 0.67 (to the hundredth)
Answer:
10 minutes
Step-by-step explanation:
First off, you want to figure out how many photos it prints in one minute. 36 divided by 8 is 4.5. So you should add 4.5 to 36, which makes 40.5 in 9 minutes. Add another 4.5 and you get 45 which you should add another minute. That gives you 10 minutes.
Another way is to find how many per minute which would again be 4.5. 45 divided by 4.5 is 10. So once again, 10 minutes.