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2 years ago

I give up.. please don’t just answer for points PLEASEE HELP MEEE if u get it right then i swear i owe you a brainliest :P

Mathematics

2 answers:

Ipatiy [6.2K]2 years ago

5 0

Answer:

B. or C.

Step-by-step explanation:

- hope this helps

Mariulka [41]2 years ago

4 0

Answer:

B and D

Step-by-step explanation:

If you count all of the dots, you see that the total amount of math books is 12.

Then, look at the column between 2 and 2 2/8. You see that there are 2 books that weigh 2 1/8 pounds.

Therefore, there are 2 out of the 12 books that weigh 2 1/8 pounds.

2/12 can also be simplified down to 1/6.

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Can anyone help me on 4,7,10 Using simplest form

dezoksy [38]

I will give the answers, you can comment any questions! Glad to help you!!!

4.) 7/8

7.) 9/10

10.)1 1/6

Hope this helps!

Comment any questions!

7 0

3 years ago

What is the least common multiple of 8 and 12? 24 48 96

Anna007 [38]

Answer:

The least common multiple of 8 and 12 is 24

Explanation:

Find and list the multiples each number until the first common multiple is found.

This is the lowest common multiple .

Multiples of 8

8, 16, 24, 32,40

Multiples of 12

12,24, 36,48

Therefore,

LCM of 8 and 12 is 24

3 0

2 years ago

Read 2 more answers

A building has an entry the shape of a parabolic arch 22 ft high and 28 ft wide at the base, as shown below.

Ivenika [448]

The parabola is at Max of 22

5 0

2 years ago

A simple random sample of size nequals81 is obtained from a population with mu equals 83 and sigma equals 27. (a) Describe the

Ivanshal [37]

Answer:

a) $\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

b) $z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

c) $z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

d) $z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

Step-by-step explanation:

For this case we know the following propoertis for the random variable X

$\mu = 83, \sigma = 27$

We select a sample size of n = 81

Part a

Since the sample size is large enough we can use the central limit distribution and the distribution for the sampel mean on this case would be:

$\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

Part b

We want this probability:

$P(\bar X>89)$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 89 we got:

$z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

Part c

$P(\bar X$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 75.65 we got:

$z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

Part d

We want this probability:

$P(79.4 < \bar X < 89.3)$

We find the z scores:

$z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

8 0

3 years ago

In the morning the temperature was -9°F The temperature increased by

Alexeev081 [22]

Answer:

Step-by-step explanation:

4 0

2 years ago