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3 years ago

I give up.. please don’t just answer for points PLEASEE HELP MEEE if u get it right then i swear i owe you a brainliest :P

Mathematics

2 answers:

Ipatiy [6.2K]3 years ago

5 0

Answer:

B. or C.

Step-by-step explanation:

- hope this helps

Mariulka [41]3 years ago

4 0

Answer:

B and D

Step-by-step explanation:

If you count all of the dots, you see that the total amount of math books is 12.

Then, look at the column between 2 and 2 2/8. You see that there are 2 books that weigh 2 1/8 pounds.

Therefore, there are 2 out of the 12 books that weigh 2 1/8 pounds.

2/12 can also be simplified down to 1/6.

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At sea, the distance D to the horizon is directly proportional to the square root of the elevation E of the observer. If a perso

Alla [95]

The problem says that the distance D to the horizon is directly proportional to the square root of the elevation E of the observer, so:

The person who is 36 feet above the water ⇒ √36=6

A person 49 feet above the water ⇒ √49=7

So, by proportions, you have:

(7/6)x7.4= 8.63 miles

Therefore, the answer is: a person 49 feet above the water can see 8.63 miles

7 0

3 years ago

Which expression is equivalent to x^2+2x+2

Aneli [31]

Do not click on that oh and I think the answer is a

8 0

3 years ago

Find the perimeter of WXYZ. Round to the nearest tenth if necessary.

yanalaym [24]

Answer:

C. 15.6

Step-by-step explanation:

Perimeter of WXYZ = WX + XY + YZ + ZW

Use the distance formula, $d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$ to calculate the length of each segment.

✔️Distance between W(-1, 1) and X(1, 2):

Let,

$W(-1, 1) = (x_1, y_1)$

$X(1, 2) = (x_2, y_2)$

Plug in the values

$WX = \sqrt{(1 - (-1))^2 + (2 - 1)^2}$

$WX = \sqrt{(2)^2 + (1)^2}$

$WX = \sqrt{4 + 1}$

$WX = \sqrt{5}$

$WX = 2.24$

✔️Distance between X(1, 2) and Y(2, -4)

Let,

$X(1, 2) = (x_1, y_1)$

$Y(2, -4) = (x_2, y_2)$

Plug in the values

$XY = \sqrt{(2 - 1)^2 + (-4 - 2)^2}$

$XY = \sqrt{(1)^2 + (-6)^2}$

$XY = \sqrt{1 + 36}$

$XY = \sqrt{37}$

$XY = 6.08$

✔️Distance between Y(2, -4) and Z(-2, -1)

Let,

$Y(2, -4) = (x_1, y_1)$

$Z(-2, -1) = (x_2, y_2)$

Plug in the values

$YZ = \sqrt{(-2 - 2)^2 + (-1 -(-4))^2}$

$YZ = \sqrt{(-4)^2 + (3)^2}$

$YZ = \sqrt{16 + 9}$

$YZ = \sqrt{25}$

$YZ = 5$

✔️Distance between Z(-2, -1) and W(-1, 1)

Let,

$Z(-2, -1) = (x_1, y_1)$

$W(-1, 1) = (x_2, y_2)$

Plug in the values

$ZW = \sqrt{(-1 -(-2))^2 + (1 - (-1))^2}$

$ZW = \sqrt{(1)^2 + (2)^2}$

$ZW = \sqrt{1 + 4}$

$ZW = \sqrt{5}$

$ZW = 2.24$

✅Perimeter = 2.24 + 6.08 + 5 + 2.24 = 15.56

≈ 15.6

5 0

3 years ago

Explain how this solid figure can be broken up in two different ways.

den301095 [7]

Answer:

wheres the figure ??

Step-by-step explanation:

3 0

3 years ago

Evaluate the given integral by making an appropriate change of variables, where r is the rectangle enclosed by the lines x - y =

vova2212 [387]

$\begin{cases}u=x-y\\v=x+y\end{cases}$

$\mathbf J=\dfrac{\partial(u,v)}{\partial(x,y)}=\begin{bmatrix}\dfrac{\partial u}{\partial x}&\dfrac{\partial u}{\partial y}\\\\\dfrac{\partial v}{\partial x}&\dfrac{\partial v}{\partial y}\end{bmatrix}=\begin{bmatrix}1&-1\\1&1\end{bmatrix}$
$\implies\det\mathbf J=2$

The area of the region is then given by

$\displaystyle\iint_R\mathrm dA=\int_{u=0}^{u=7}\int_{v=0}^{v=6}2\,\mathrm dv\,\mathrm du=84$

6 0

3 years ago