Answer:
2
Step-by-step explanation:
the answer is number 2 dm me for more info
A. AAS
B. SAS
C. ASA
Just look at what order they come in. Lmk if you need further help.
Answer:
Step-by-step explanation:
Given the coordinate points (6, -3) and (7, -10), we are to find the equation of a line passing through this two points;
The standard equation of a line is y = mx+c
m is the slope
c is the intercept
Get the slope;
m = Δy/Δx = y2-y1/x2-x1
m = -10-(-3)/7-6
m = -10+3/1
m = -7
Get the intercept;
Substitute the point (6, -3) and m = -7 into the expression y = mx+c
-3 = -7(6)+c
-3 = -42 + c
c = -3 + 42
c = 39
Get the required equation by substituting m = -7 and c= 39 into the equation y = mx+c
y = -7x + 39
Hence the required equation is y = -7x + 39
Answer:
{x,y} = {89/37,-71/37}
Step-by-step explanation:
8x = 3y + 25
[2] x = 3y/8 + 25/8
Plug this in for variable x in equation [1]
[1] 6•(3y/8+25/8) + 7y = 1
[1] 37y/4 = -71/4
[1] 37y = -71
Solve equation [1] for the variable y
[1] 37y = - 71
[1] y = - 71/37
By now we know this much :
x = 3y/8+25/8
y = -71/37
Use the y value to solve for x
x = (3/8)(-71/37)+25/8 = 89/37
