It took a sled dog team 8.5 hours to travel 161.5 Kilometers. What was the average speed of the sled dog team in Kilometers per
2 answers:
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240 inches cut into 2 equal pieces is just taking half of the wire.
Making the two pieces of wire 120 inches.
If you bend one 120 inch wire into a square, that means that each side equals 30 inches. (A square has 4 sides. 120/4 = 30)
An area of a square is length times width, which the length equals 30 and width equal to thirty. 30 * 30 = 900. square inches.
120 wire bent into a triangle makes each side equal to 40. 120/3=40. The area of an equilateral triangle is height times width. The width is just one of the sides (40 inches) but the height needs some geometry. To find the height you need to use either 30 times sin(60) or 30 times cos(30), both are equal. To be clear, I will leave the height as 30sin(60). The area will be equal to
which can be simply written as 1200sin(60).
So the sum of both areas is
Making the two pieces of wire 120 inches.
If you bend one 120 inch wire into a square, that means that each side equals 30 inches. (A square has 4 sides. 120/4 = 30)
An area of a square is length times width, which the length equals 30 and width equal to thirty. 30 * 30 = 900. square inches.
120 wire bent into a triangle makes each side equal to 40. 120/3=40. The area of an equilateral triangle is height times width. The width is just one of the sides (40 inches) but the height needs some geometry. To find the height you need to use either 30 times sin(60) or 30 times cos(30), both are equal. To be clear, I will leave the height as 30sin(60). The area will be equal to
which can be simply written as 1200sin(60).
So the sum of both areas is
Answer:
y+3=-4(x-5)
Explanation:
Part A
Given the line:
We want to find the equation of a perpendicular line that passes through the point (5,-3),
First, determine the slope of the perpendicular line.
Comparing the given line with the slope-point form:
By definition, two lines are perpendicular if the product of their slopes is -1.
Let the slope of the perpendicular line = n
Thus, using a slope of -4 and a point (5,-3), we find the equation of the line.
The equation of the perpendicular line in the slope-point form is:
Part B
In order to graph the line, first, find two points on the line.
When x=0
When y=1
Join the points (0,17) and (4,1) as shown in the graph below:
