What's the area of this?

What is the definition for center

vlada-n [284]

Answer:

the center- like- of a bowel- is the middle- bru.h im trying to be mean but ;-;

Step-by-step explanation:

6 0

3 years ago

Calculate the length of the circumference of a circle with a diameter of 4cm

MakcuM [25]

Length of circumference is 2πr
2 π r and r is equal to 2 cm
I.e 12.5 cm

6 0

3 years ago

The x co-ordinate of any point lying on the Y axis is: please help urgent

olchik [2.2K]

Answer:

x-coordinate = 0

Step-by-step explanation:

In a coordinate plan there are two perpendicular lines one is x-axis and another is y-axis

x-axis is a horizontal line and y-axis is a vertical line.

Both lines intersect each other at (0,0).

On x-axis, y-coordinate remains same , i.e., y=0.

On y-axis, x-coordinate remains same , i.e., x=0.

Therefore, the x co-ordinate of any point lying on the y axis is 0.

8 0

3 years ago

The length of a rectangle is twice its breadth. If its perimeter is 60 cm, find the length and the breadth of the rectangle

Vaselesa [24]

Answer:

Length is <u>20 cm</u>
Breadth is <u>10 cm</u>

Step-by-step explanation:

<h3>According to the Question</h3>

It is given that,

Length of rectangle is twice as its breadth
Perimeter of Rectangle = 60cm

We have to calculate the length and

breadth of the rectangle.

Let the breadth be x cm.

then,

Length be 2x cm.

Calculating the length and breadth-

Perimeter of Rectangle = 2(Length+breadth)

By putting the value we get-

→60 = 2(2x+x)

→60 = 2(3x)

→60 = 6x

→x = 60/6

→ x = 10 cm

Since, breadth is <u>10</u> cm.

Therefore, Length = 2x = 2×10 = 20 cm.

Hence, the length and breadth of rectangle is 20 cm & 10 cm respectively.

3 0

3 years ago

Read 2 more answers

A conical water tank with vertex down has a radius of 13 feet at the top and is 21 feet high. If water flows into the tank at a

VLD [36.1K]

Answer:

$\frac{dh}{dt}\approx0.08622\text{ ft/min}$

Step-by-step explanation:

We know that the conical water tank has a radius of 13 feet and is 21 feet high.

We also know that water is flowing into the tank at a rate of 30ft³/min. In other words, our derivative of the volume with respect to time t is:

$\frac{dV}{dt}=\frac{30\text{ ft}^3}{\text{min}}$

We want to find how fast the depth of the water is increasing when the water is 17 feet deep. So, we want to find dh/dt.

First, remember that the volume for a cone is given by the formula:

$V=\frac{1}{3}\pi r^2h$

We want to find dh/dt. So, let's take the derivative of both sides with respect to the time t. However, first, let's put the equation in terms of h.

We can see that we have two similar triangles. So, we can write the following proportion:

$\frac{r}{h}=\frac{13}{21}$

Multiply both sides by h:

$r=\frac{13}{21}h$

So, let's substitute this in r:

$V=\frac{1}{3}\pi (\frac{13}{21}h)^2h$

Square:

$V=\frac{1}{3}\pi (\frac{169}{441}h^2)h$

Simplify:

$V=\frac{169}{1323}\pi h^3$

Now, let's take the derivative of both sides with respect to t:

$\frac{d}{dt}[V]=\frac{d}{dt}[\frac{169}{1323}\pi h^3}]$

Simplify:

$\frac{dV}{dt}=\frac{169}{1323}\pi \frac{d}{dt}[h^3}]$

Differentiate implicitly. This yields:

$\frac{dV}{dt}=\frac{169}{1323}\pi (3h^2)\frac{dh}{dt}$

We want to find dh/dt when the water is 17 feet deep. So, let's substitute 17 for h. Also, let's substitute 30 for dV/dt. This yields:

$30=\frac{169}{1323}\pi (3(17)^2)\frac{dh}{dt}$

Evaluate:

$30=\frac{146523}{1323}\pi( \frac{dh}{dt})$

Multiply both sides by 1323:

$39690=146523\pi\frac{dh}{dt}$

Solve for dh/dt:

$\frac{dh}{dt}=\frac{39690}{146523}\pi$

Use a calculator. So:

$\frac{dh}{dt}\approx0.08622\text{ ft/min}$

The water is rising at a rate of approximately 0.086 feet per minute.

And we're done!

Edit: Forgot the picture :)

3 0

3 years ago

What's the area of this?​

What's the area of this?