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Zolol [24]
2 years ago
12

A number that has four identical even

Mathematics
2 answers:
evablogger [386]2 years ago
6 0

Answer:

210?

Step-by-step explanation:

210 has factors of 2, 3, 5, and 7

ycow [4]2 years ago
4 0
The answer is 16

Explanation
Number has 4 factors
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What is the area of the prism
babymother [125]

Answer: 72

Step-by-step explanation:

Prism area = b * h

base = 4 * 3 = 12

height = 6

12 * 6 = 72

8 0
3 years ago
Read 2 more answers
3x-32=-7×+28. what does x =​
Vitek1552 [10]

Hello!

3x - 32 = -7x + 28

-32 - 28 = -7x - 3x

-60 = -10x

-6 = -x

6 = x

x = 6

I hope this helps you! Have a lovely day!

- Mal

3 0
3 years ago
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Landon owns a hybrid SUV that can travel 400 miles on a 15 gallon tank of gas. Determine how many miles he can travel in 6 gallo
arlik [135]
Set this up as a proportion.

400/15 = x/6

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8 0
3 years ago
-6 = u/ -1 +-4 what's u
yuradex [85]

Answer:

the answer to your question is U=2

Step-by-step explanation:

6 0
2 years ago
Find the values of λ for which the determinant is zero.
elena55 [62]

Answer:

Determinant are special number that can only be defined for square matrices.

Step-by-step explanation:

Determinant are particularly important for analysis. The inverse of a matrix exist, if the determinant is not equal to zero.

How to find determinant

For a 2×2 matrix

det ( \left[\begin{array}{cc}x&y\\a&z\end{array}\right] ) = xz-ay

For a 3×3 matrix

we first decompose it to 2×2

det (\left[\begin{array}{ccc}k&l&m\\o&p&q\\r&s&t\end{array}\right] )\\\\= k*det(\left[\begin{array}{cc}p&q\\s&t\end{array}\right] ) - l*det(\left[\begin{array}{cc}o&q\\r&t\end{array}\right] ) + m*det(\left[\begin{array}{cc}o&p\\r&s\end{array}\right] ) \\\\=k(pt-sq) - l(ot-rq) + m(os-rp)

Example

Find the values of λ for which the determinant is zero

\left[\begin{array}{ccc}s&-1&0\\-1&s&-1\\0&-1&1\end{array}\right]

det(\left[\begin{array}{ccc}s&-1&0\\-1&s&-1\\0&-1&1\end{array}\right])\\\\= s*det(\left[\begin{array}{cc}s&-1\\-1&1\end{array}\right] ) - (-1)*det(\left[\begin{array}{cc}-1&-1\\0&1\end{array}\right] ) + 0*det(\left[\begin{array}{cc}-1&s\\0&-1\end{array}\right] )\\\\= s(s(1)-(-1*-1)) - (-1)(-1*1 - (-1*0)) + 0\\= s(s - 1)) + 1(-1 + 0) \\=s^{2} -s-1

Equating the determinant to zero

s^{2} -s-1 =0\\

s = \frac{1}{2} * (1 ±5 )

s = 1.61 or -0.61

5 0
3 years ago
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