Answer:
H = V0y t - 1/2 g t^2 equation for vertical height of object with initial speed (V0y = V0 sin theta)
If H is to be considered an absolute value from t = 0
h = H + 3 = V0y t - 1/2 g t^2 + 3 where h is height from ground
192 = 2 * 2 * 2 * 2 * 2 * 2 * 3 =
= 2^(6) * 3
√ 192 = √( 2^(6) * 3 =
= 2^(3) √ 3 = 8 √ 3 - in simple radical form.
( 8√3 ) ² = 64 * 3 = 192
Answer:
√ 192 = 8 √ 3
Answer:
y=1/2x-4
Step-by-step explanation:
2y-x=-8
2y=x-8
y=1/2x-4
Answer:
y = 4
Step-by-step explanation:
y = 4
The line will always go along y = 4 and therefore is parallel to the x axis
