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2 years ago

Show work please thank you

Mathematics

1 answer:

Alenkinab [10]2 years ago

8 0

Hey there!:)

b1+b2
--------- x h =area
2

(3+5)/2h=area

8/2h=area

4(2)=area
area= 8ft squared (this is your answer)

Hope this helps! Let me know if you need more help:)

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The number 21 is what percent of 75

lesantik [10]

Answer:

28 percent

Step-by-step explanation:

To find what percentage of a number another number is, you can basically just divide it, 21/75 then you can multiply it by 100, so 21/75=0.28, and then 0.28*100=28, 21 is 28 percent of 75

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3 years ago

A rectangle has two different side lengths: One is (4p-5) inches. The other is (3p+2) inches. Find the perimeter of the rectangl

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The perimeter of rectangle is 14p-6.

Step-by-step explanation:

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3 years ago

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2 years ago

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SVETLANKA909090 [29]

$y = e^x\\\\\displaystyle y = \sum_{k=1}^{\infty}\frac{x^k}{k!}\\\\\displaystyle y= 1+x+\frac{x^2}{2!} + \frac{x^3}{3!}+\ldots\\\\\displaystyle y' = \frac{d}{dx}\left( 1+x+\frac{x^2}{2!} + \frac{x^3}{3!}+\frac{x^4}{4!}+\ldots\right)\\\\$

$\displaystyle y' = \frac{d}{dx}\left(1\right)+\frac{d}{dx}\left(x\right)+\frac{d}{dx}\left(\frac{x^2}{2!}\right) + \frac{d}{dx}\left(\frac{x^3}{3!}\right) + \frac{d}{dx}\left(\frac{x^4}{4!}\right)+\ldots\\\\\displaystyle y' = 0+1+\frac{2x^1}{2*1} + \frac{3x^2}{3*2!} + \frac{4x^3}{4*3!}+\ldots\\\\\displaystyle y' = 1 + x + \frac{x^2}{2!}+ \frac{x^3}{3!}+\ldots\\\\\displaystyle y' = \sum_{k=1}^{\infty}\frac{x^k}{k!}\\\\\displaystyle y' = e^{x}\\\\$

This shows that $y' = y$ is true when $y = e^x$

-----------------------

Note 1: A more general solution is $y = Ce^x$ for some constant C.
Note 2: It might be tempting to say the general solution is $y = e^x+C$ , but that is not the case because $y = e^x+C \to y' = e^x+0 = e^x$ and we can see that $y' = y$ would only be true for C = 0, so that is why $y = e^x+C$ does not work.

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