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garik1379 [7]
3 years ago
9

Solve 3/4x = 7 28/ 3​

Mathematics
1 answer:
Olegator [25]3 years ago
6 0

3/4x=728/3

x=728/3×4/3

x=32.556

HOPE IT HELPS YOU OUT PLEASE MARK IT AS BRAINLIEST AND FOLLOW ME PROMISE YOU TO FOLLOW BACK ON BRAINLY.IN

BUT I'M NOT SURE IF IT IS CORRECT

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Which expression is equivalent to 16^2 − 36? (Explain)
seropon [69]

Answer:

4(2x-3)(2x + 3)

Step-by-step explanation:

Here, we want to simplify the given expression

we can have;

16x^2-36

= 4(4x^2 -9)

we can use the difference of two squares

where;

a^2 - b^2 = (a-b)(a + b)

= 4(2x-3)(2x+ 3)

6 0
2 years ago
Can someone please tell me if any of my answers are wrong!????
ra1l [238]

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5 0
3 years ago
− 4 x + 12 −4x+12 y=x
Lelu [443]

Answer:

3x-4y=4

Step-by-step explanation:

7 0
2 years ago
Find the least common multiple of x2 – 8x + 12 and x2 – x – 2.
abruzzese [7]
<span>The least common multiple of x² – 8x + 12 and x² – x – 2.

by factoring:
∴ </span><span>x² – 8x + 12 = (x-2)(x-6)

       </span><span>x² – x – 2 = (x-2)(x+1)

note: the factor (x-2) is common between them take it one time

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</span>
6 0
3 years ago
Read 2 more answers
Un submarino se encuentra 50m por debajo del nivel del mar y comienza a subir 2m cada 5 minutos ¿a que profundidad se encuentra
Trava [24]

Answer:

a) El submarino se encuentra a una profundidad de 26 metros una hora después de haber comenzado el ascenso.

b) Al submarino le falta 1 hora y 5 minutos para llegar a la superficie.

Step-by-step explanation:

a) De acuerdo con el enunciado, la cantidad de metros ascendidos por el submarino es directamente proporcional al tiempo, entonces la profundidad del submarino a la hora de haber comenzado el ascenso se obtiene mediante la siguiente relación lineal:

h = 50\,m - \frac{2\,m}{5\,min}\times 60\,min

h = 26\,m

El submarino se encuentra a una profundidad de 26 metros una hora después de haber comenzado el ascenso.

b) En primer lugar, calculamos el tiempo total del viaje mediante la siguiente relación:

\frac{2\,m}{5\,min} = \frac{50\,m}{t}

t = 50\,m\times \frac{5\,min}{2\,m}

t = 125\,min (2\,h\,5\,min)

El tiempo faltante para alcanzar la superficie se calcula mediante la siguiente sustracción:

\Delta t = 125\,min - 60\,min

\Delta t = 65\,min (1\,h\,5\,min)

Al submarino le falta 1 hora y 5 minutos para llegar a la superficie.

7 0
3 years ago
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