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3 years ago

What might happen if transformers didn't exist?

Physics

2 answers:

Liula [17]3 years ago

5 0

I think it’s B idk if I’m right

Law Incorporation [45]3 years ago

4 0

Answer:

The electricity in your house might have an extremely high voltage

Explanation:

To travel efficitenly elelectricty needs to be at a high voltage and transformers take it town to a resonable level.

You might be interested in

Mercury's surface has many craters because _____.

Alexeev081 [22]

I think it would be that it has no atmosphere

5 0

3 years ago

The temperature of a smelting furnace is found to be 2000 degree Celsius.find the temperature on Fahrenheit scale

Dima020 [189]

Answer:

3632.

Explanation:

Based on the formula:

2000×(9/5)+32=3632

6 0

3 years ago

A physical pendulum in the form of a planar object moves in simple harmonic motion with a frequency of 0.290 Hz. The pendulum ha

BARSIC [14]

Answer:

1.4584 kg $m^2$

Explanation:

Time period of a physical pendulum is given by $T=2Π\sqrt{\frac{I}{mgd}}$

Here f=0.290 so $T=\frac{1}{F}=\frac{1}{0.29}=3.44827$

Mass =2.40 kg

d=0.300 m

g =9.8 m $sec^2$

So $3.448=2\times \pi \sqrt{\frac{I}{2.4\times 9.81\times 0.300}}=1.4584$ kg- $m^2$

So the moment of inertia of the pendulum about the pivot point will be 1.4584 kg- $m^2$

7 0

3 years ago

If a cotton ball is dropped from 12 meters with air resistance, what will be the velocity and acceleration at t = 1.00 s?

kifflom [539]

That depends on the weight, shape, size, density, and moisture content
of the cotton ball, as well as on the length, shape, thickness, and surface
texture of every little cotton fiber sticking out of it.

Now you know why we typically ignore air resistance when we work with
objects falling in gravity.

4 0

4 years ago

A force in the x direction acts on a particle moving also in the x direction, producing a potential energy U(x)=Ax4 where A=0.63

poizon [28]

Answer:

The magnitude of the force is 1.29*10^-3N in the positive x direction

Explanation:

In order to calculate the magnitude and direction of the force, you take into account that the force is the space derivative of the potential enrgy, as follow:

$F(x)=-\frac{dU(x)}{dx}$ (1)

where:

$U(x)=Ax^4\\\\A=0.0630\frac{J}{m^4}$

You replace the expression for U into the equation (1) and solve for F:

$F(x)=-\frac{d}{dx}[Ax^4]=-4Ax^3$ (2)

The force on the particle, for x = -0.080m is:

$F=-4(0.630\frac{J}{m^4})(-0.0800m)^3=1.29*10^{-3}N$

The magnitude of the force is 1.29*10^-3N in the positive x direction

7 0

3 years ago