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Mademuasel [1]
4 years ago
6

a motorcycle starting from rest has an acceleration of 2.6m/s how long does it take the motorcycle to travel a distance of 120

Physics
1 answer:
Setler79 [48]4 years ago
5 0
46.15 seconds to reach 120
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Help me please <br>only if you really know​
emmasim [6.3K]

Assume <em>R</em> is measured in meters (m) and <em>M</em> in kilograms (kg). Then

<em>R</em> ² / (<em>GM</em>) = [m]² / ([N•m²/kg²] [kg]) = m•kg / N = m•kg / (kg•m/s²) = s²

so <em>t</em> ² is indeed proportional to <em>R</em> ²/(<em>GM</em>).

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3 years ago
Can anyone help me on question 13
Leona [35]

Given that in a parallel circuit:

R1 = 12 ohms

R2= 15 ohms

I = 12 A

I2 = 4 A

V=?

R=?

R3 =?

P=?

Since,

V= IR

or,

V2 = I2 * R2

V2= 4* 15

V2 = 60V

Since in a parallel circuit voltage remain same in all component of the circuit and is equal to the source voltage.

Therefore,

V= V1 = V2 = V3 = 60V

Since,

V= IR

R= V/I

R= 60/12

R= 5 ohm

That is total resistance is equal to 5 ohms.

Since for parallel circuit,

1/R= 1/R1 + 1/R2 + 1/R3

1/5= 1/12+ 1/15 + 1/R3

or

1/R3= 1/5- 1/12- 1/15

1/R3= 1/20

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R3= 20 ohms

Since,

V=IR

I= V/R

I1= V1/ R1

I1= 60/12

I1= 5 A

I3= V3/R3

I3= 60/20

I3= 3A

Since,

P=VI

P= 60*12

P=  720 watt

P1= V1* I1

P1= 60* 5

P1= 300 watt

P2= V2* I2

P2= 60* 4

P2= 240watt

P3= V3*I3

P3= 60*3

P3= 180 watt

Hence we have,

R1= 12 ohms , R2= 15 ohms, R3= 20 ohms, R= 5 ohms

I1= 5A, I2= 4A, I3= 3A, I= 12 A

V1= V2= V3= V= 60V

P1= 300 watt, P2= 240 watt, P3 = 180 watt, P= 720 watt



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3 years ago
What types of energy are produced during firework displays?
-Dominant- [34]

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some of the chemical energylocked inside them is converted into four other kinds of energy (heat, light, sound, and the kinetic energy of movement). According to a basic law of physics called the conservation of energy.

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3 years ago
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In a physics lab, a 60-kg student runs up a 2.0-meter tall flight of stairs in 1.5 seconds. The work done to get to the top is 1
tester [92]
<span>The student's power rating is approximately 800W.
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Power is the rate of doing work. Its SI unit is Watt. 1 W = 1J/sec

Given: <span>The work done to get to the top is 1200 Joules
</span>
Time = 1.5 seconds.

Power = \frac{work done}{time} &#10;=  \frac{1200J}{1.5 sec} &#10;= 800J/sec &#10;= 800W
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4 years ago
If the water measures -5 feet at low tide and 3ft at high tide what is the tidal range ​
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