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3 years ago

Why would it be very hard to land aspeceship on Saturn?

Physics

1 answer:

gtnhenbr [62]3 years ago

7 0

Very it would most likely get crushed by the pressure of all the gas before landing.

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A 14.3-g bullet is fired into a 5.21 kg block of wood. The block is attached to a spring that has a spring force constant of 450

Natasha2012 [34]

Answer:

The initial speed of the bullet is $v_{o} = 889.199\,\frac{m}{s}$ .

Explanation:

The collision between bullet and block is inelastic and let suppose that motion occurs on a horizontal surface, so that changes in gravitational potential energy can be neglected. Initially, the intial speed of the bullet-block system can be determined with the help of the Work-Energy Theorem and the Principle of Energy Conservation:

$K = U_{k} + W_{loss}$

$\frac{1}{2}\cdot (5.224\,kg)\cdot v^{2} = \frac{1}{2}\cdot \left(450\,\frac{N}{m}\right)\cdot (0.22\,m)^{2} + (0.35)\cdot (5.224\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right) \cdot (0.22\,m)$

The initial speed of the bullet-block system is:

$v \approx 2.383\,\frac{m}{s}$

Now, the initial speed of the bullet is determined by applying the Principle of Momentum Conservation:

$(0.014\,kg)\cdot v_{o} = (5.224\,kg)\cdot \left(2.383\,\frac{m}{s} \right)$

$v_{o} = 889.199\,\frac{m}{s}$

6 0

3 years ago

A submarine sends out a sonar signal (sound waves) in a direction directly downward it take 2.3 s for the sound waves to travel

NISA [10]

Explanation:

Using the formula;

2x = vt

x is the distance up from the ocean floor the submarine is

v is the speed of sound in water

t is the time

Given

t = 2.3s

v = 1490m/s

Required

how high (approx) up from the ocean floor is the submarine x

From the formula;

x = vt/2

x = 1490(2.3)/2

x = 745(2.3)

x = 1,713.5m

Hence the submarine is 1713.5m high up from the ocean floor

5 0

3 years ago

You are the science officer on a visit to a distant solar system. Prior to landing on a planet you measure its diameter to be 1.

Alja [10]

Answer:

Part a)

$M = 7.25 \times 10^{25} kg$

Part b)

$M = 2\times 10^{30} kg$

Explanation:

Part a)

As we know that the diameter of the planet is given as

$d = 1.8 \times 10^7 m$

now the radius of the planet is given as

$r = 9 \times 10^6 m$

now we know that the acceleration due to gravity of the planet is given by the equation

$g = \frac{GM}{r^2}$

here we know that

$g = 59.7 m/s^2$

now from above equation we have

$59.7 = \frac{(6.67 \times 10^{-11})M}{(9\times 10^6)^2}$

now we have

$M = 7.25 \times 10^{25} kg$

Part b)

Now by kepler's law we know that

time period of revolution of planet about the star is given as

$T = 2\pi \sqrt{\frac{r^3}{GM}}$

so we have

$\frac{T_1^2}{T_2^2} = \frac{r_1^3}{r_2^3}$

now we have

$\frac{1^2}{402^2} = \frac{(1.5 \times 10^11)^3}{r^3}}$

$rr = 8.17 \times 10^{12} m$

mula of time period

$402\times (365\times 24 \times 3600) = 2\pi \sqrt{\frac{(8.17\times 10^12)^3}{(6.67\times 10^{-11})M}}$

Now we have

$M = 2\times 10^{30} kg$

7 0

3 years ago

As thermal energy is added to a sample of water, the kinetic energy of its

Nesterboy [21]

Answer:

Explanation:

3 0

3 years ago

Using r.i.v.p. How do I calculate circuits wit 12 volts

Reil [10]

You don't calculate a circuit. You calculate the voltage, current, capacitance,
resistance, inductance, impedance, phase, power factor, frequency response,
or reflection coefficient of the circuit, and other stuff like that there.

Tell us what you need to find, and what information you have, and we'll
show you how to use what you have to find what you need to find.

4 0

3 years ago