Answer:
6 rad/s
Explanation:
In a spring the angular frequency is calculated as follows:
where 
is the angular frequency, 
is the mass of the object in this case 
, and 
is the constant of the spring.
To calculate the angular frequency, first we need to find the constant which is calculated as follows:
Where 
is the force: 
, and 
is the distance from the equilibrium position: 
.
Thus the spring constant:
And now we do have everything necessary to calculate the angular frequency:
the angular frequency of the oscillation is 6 rad/s
Explanation:
It is given that,
The velocity of a particle is given by :
Where
v is in m/s and t is in seconds
Let a is the acceleration of the object at time t. So,
When a = 0
t = 2.5 s
a is zero at t = 2.5 s. Velocity, 
v = -75 m/s
Since, 
, s is the distance travelled
At t = 2.5 s, 
s = −83.34 m
Hence, this is the required solution.
Answer: D (doubled)
According to ohm's law
I = V/R ,
V = IR ; R = constant and V is doubled
From the equation
V is directly proportional to the current, and it is given that R is constant ;
2V = 2I. R since R = constant
Hence I is doubled.
Answer: Mabye like an ocean with dolphins swiming/jumping? Or even use the blue as a sky and then put green grass and do foxes or and a phoenix flying with a fox under it?
Explanation:
Just some ideas!
Answer:
the work done by the 30N force is 4156.92 J.
For this problem, they don´t ask you to determine the work of the total force applied in the block. They only want the work done for the force of 30N, with an angle of 30º respectively of the displacement and a traveled distance of 160m. So:
W=F·s·cos(α)=30N·160m·cos(30º)=4156.92J
