Answer:
Explanation:
I believe what you're looking for is :
Opposites
Density
Could be wrong but I think so.
Answer: 2.9kg
let mass be=m ; F=15N; Sin(theta)=32°;g =9.8kgm/s^2.
represent the mass. By resolving forces, we have:
F=mgSin(theta)
15N=mgSin(32°)
m=15N/g×Sin(32°)
m=15N/9.8m/s^2÷Sin(32°)
=2.888kg2.888
≈2.9kg
Answer:
Speed acquired (Final velocity) = 12 m/s
Distance travelled = 720 meter
Explanation:
Given:
Uniform acceleration = 0.1 m/s²
Initial velocity = 0 m/s
Time taken = 2 minutes = 2 x 60 = 120 second
Find:
(a) Speed acquired (Final velocity)
(b) Distance travelled
Computation:
v = u + at
v = 0 + 0.1(120)
Speed acquired (Final velocity) = 12 m/s
Distance travelled = ut + (1/2)(a)(t²)
Distance travelled = (0)(120) + (1/2)(0.1)(120²)
Distance travelled = (1/2)(0.1)(14400)
Distance travelled = 720 meter
Answer:
1.73 seconds
Explanation:
The velocity the ball first hits the ground with is:
v² = v₀² + 2aΔx
v² = (0 m/s)² + 2 (-10 m/s²) (-20 m)
v = -20 m/s
The velocity it rebounds with is 3/4 of that in the opposite direction, or 15 m/s.
The time it takes to return to the ground is:
Δx = v₀ t + ½ at²
0 = (15 m/s) t + ½ (-10 m/s²) t²
0 = t (15 − 5t²)
t = √3
t ≈ 1.73 seconds
