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True [87]
4 years ago
8

Rectangular park 5/6 wide and 1 and 5/7 miles long what area is it HJELP DO IT SIMPLEST FORM

Mathematics
1 answer:
Hitman42 [59]4 years ago
7 0

Answer:

1 and 3/7 i think

Step-by-step explanation:

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3 years ago
The floor of a conference hall can be covered completly with tiles.Its length is 36ft. longer than its width.The area of the flo
Masteriza [31]

Answer:

Step-by-step explanation:

Given

Area of a floor = 2040ft²

If Its length is 36ft. longer than its width, then L = W+36

Area = LW

L is the length

W is the width

A <  W(W+36)

2040 < W²+36W

0<W²+36W-2040

W²+36W-2040 >0

W = -36±√36²-4(-2040)/2

W =  -36±√1296+8160)/2

W =  -36±√9456/2

W =  -36±97.25/2

W = -36+97.25/2

W = 61.24/2

W > 30.62ft

Since L = W+36

L > 30.62+36

L > 66.62ft

The width of the floor is 30.62ft

The length is 66.62ft

The mathematical sentence would represent the given situation is the width is greater than 30.62ft while the length must be greater than 66.62ft

The possible dimension of the floor is 31ft by 67 ft

The possible areas is 31*67 = 2077ft²

It won't be realistic to get an area of 144sqft because the initial area is greater than 144. Hence the feasible area will be greater than 2040ft²

5 0
3 years ago
Need help ASAP please!
Mazyrski [523]

Answer:

i think it's a

Step-by-step explanation:

6 0
3 years ago
2- log 6-log 9<br> In condensing
Tju [1.3M]

Answer:

\log(150)

Step-by-step explanation:

We want to rewrite the following as a single logarithm:

2 -  log(6)  -  log(9)

We introduce logarithm in the first term to get:

2  \log(10)  -  \log(6)  -  \log(9)

Recall that:

log(a)  -   log(b)  = \log \frac{a}{b}

We apply this property to get:

2 log(10)  -  log( \frac{6}{9} )

This gives:

log( {10}^{2} )  -  log( \frac{6}{9} )

log( {100})  -  log( \frac{2}{3} )

log( \frac{100}{ \frac{2}{3} } ) =  log( \frac{300}{2} )  =  log(150)

4 0
3 years ago
Sanjay2009jsanjay2009jsanjay2009j
charle [14.2K]
What does that mean ? i’m confused
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3 years ago
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