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True [87]
3 years ago
8

Rectangular park 5/6 wide and 1 and 5/7 miles long what area is it HJELP DO IT SIMPLEST FORM

Mathematics
1 answer:
Hitman42 [59]3 years ago
7 0

Answer:

1 and 3/7 i think

Step-by-step explanation:

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Graph x > -3x>−3x, is greater than, minus, 3.
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It just is :). Ok ok
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5 less than half a number, x<br><br> please help i will give you the brainliest answer
Karo-lina-s [1.5K]

Answer: 1/2x -5

Step-by-step explanation:

Half of x , less 5. (5 less just means subtract)

5 0
3 years ago
Please help me find the answer! Please explain how you got it!
Ksenya-84 [330]

Answer:

B. 4.5c + 4 = 24

Step-by-step explanation:

T = cx + py  is the equation you are given.

T = 24 because it is the total amount of money you can spend.

x = 4.5 because each phone case costs 4.50 dollars

p = 2 because you bought 2 pop sockets.

y = 2 because each pop socket costs 2 dollars.

There is no c because you don't know the number of phone cases you bought.

Now, we have to substitute the values into the equation:

24 = 4.5x + 2(2)

24 = 4.5x + 4

4.5x + 4 = 24       <--- This is your answer

Hope this helps!

7 0
3 years ago
The function f is defined by the following rule.
Leno4ka [110]
X= -4; f(x)= -15
X= 2; f(x)= 3
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6 0
3 years ago
Drag the tiles to the correct boxes to complete the palrs.
Brut [27]

Answer:

(f+g)(2)  = 4

(f-g)(4) = 8

(f ÷g)(2) = 7

(f x g)(1) = 0

Step-by-step explanation:

We are given these following functions:

f(x) = 2x + 3

g(x) = x - 1

(f+g)(2)

(f+g)(x) = f(x) + g(x) = 2x + 3 + x - 1 = 3x - 2

At x = 2

(f+g)(2) = 3(2) - 2 = 6 - 2 = 4

Then

(f+g)(2)  = 4

(f-g)(4)

(f-g)(x) = f(x) - g(x) = 2x + 3 - (x - 1) = 2x + 3 - x + 1 = x + 4

At x = 4

(f-g)(4) = 4 + 4 = 8

Then

(f-g)(4) = 8

(f ÷g)(2)

(f \div g)(x) = \frac{f(x)}{g(x)} = \frac{2x+3}{x-1}

At x = 2

(f \div g)(2) = \frac{7}{1} = 7

Then

(f ÷g)(2) = 7

(f x g)(1)

(f \times g)(x) = f(x)g(x) = (2x+3)(x-1) = 2x^2 -2x + 3x - 3 = 2x^2 + x - 3

Then

(f \times g)(1) = 2(1)^2 + 1 - 3 = 3 + 1 - 3 = 0

So

(f x g)(1) = 0

4 0
3 years ago
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