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True [87]
3 years ago
8

Rectangular park 5/6 wide and 1 and 5/7 miles long what area is it HJELP DO IT SIMPLEST FORM

Mathematics
1 answer:
Hitman42 [59]3 years ago
7 0

Answer:

1 and 3/7 i think

Step-by-step explanation:

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The graph of a proportional relationship contains the point (−12,3)(−12,3) . What is the corresponding equation? Enter your answ
DIA [1.3K]
To find your answer you need to do y divided by x.
since x = -12 and y = 3 you do 3 ÷ -12 and you get -0.25, this as a fraction is -1/4 and this is your answer!
Hope this helped!
4 0
3 years ago
Read 2 more answers
Mary had $25,000 to invest. She invested part of that amount at 3% annual interest and part at 5% annual interest for one year.
emmasim [6.3K]
(25000-f)(.03)+.05f=1100

750-.03f+.05f=1100

750+.02f=1100

.02f=350

f=$17500

So Mary invested $17500 @ 5% and 7500 at 3% to earn $1100 in interest.


3 0
3 years ago
Find the sum of the first 13 terms in the series -5+1+7...+67
valentinak56 [21]
This is an arithmetic series with common difference 6 

S13  = (13/2)[2*-5 + (13-1)*6)]  =  403
5 0
3 years ago
a certain triangle has a perimeter of 3067 mi. the shortest side measures 71 mi less than the middle side and the longest side m
UkoKoshka [18]

Answer:

The measure of the shortest side is 851 miles

Step-by-step explanation:

Let

x ----> the measure of the shortest side

y ---> the measure of the middle side

z ---> the measure of the longest side

we know that

The perimeter of triangle is equal to

P=x+y+z

P=3,067\ mi

so

3,067=x+y+z ----> equation A

the shortest side measures 71 mi less than the middle side

so

x=y-71 ----> equation B

the longest side measures 372 mi more the the middle side

so

z=y+372 ----> equation C

substitute equation B and equation C in equation A

3,067=(y-71)+y+(y+372)

solve for y

3,067=3y+301\\3y=2,766\\y=922

Find the value of x

x=y-71\\x=922-71\\x=851

therefore

The measure of the shortest side is 851 miles

6 0
3 years ago
Help, I’m stuck. Thank you very much
ZanzabumX [31]
If you notice, the container is really just two circles, with a diameter of 4 each, and a square with sides of 10.5.

now, if we just get the area of each circle, keeping in mind their radius is half of the diameter, namely r = 2, and get the area of the 10.5x10.5 square, sum them up, that'd be the surface area of the container.

\bf \stackrel{\textit{2 circle's area}}{2(\pi r^2)}~~+~~\stackrel{\textit{area of the square}}{10.5\cdot 10.5}
\\\\\\
\stackrel{\textit{2 circle's area}}{2(\pi 2^2)}~~+~~\stackrel{\textit{area of the square}}{10.5\cdot 10.5}\implies 8\pi + 110.25
5 0
3 years ago
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