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Nimfa-mama [501]
3 years ago
7

If two samples A and B had the same mean and standard deviation, but sample A had a larger sample size, which sample would have

the wider 95% confidence interval? Sample A as it comes first Sample B as its sample is more dispersed Sample A as it has the larger sample Sample B as it has the smaller sample
Mathematics
1 answer:
Advocard [28]3 years ago
7 0
<h3>Answer: Sample B as it has the smaller sample (choice #4)</h3>

===========================================================

Explanation:

Recall that the margin of error (MOE) is defined as

MOE = z*s/sqrt(n)

The sample size n is located in the denominator, meaning that as n gets bigger, the MOE gets smaller. The same happens in reverse: as n gets smaller, the MOE gets bigger.

Put another way, a small sample size means we have more error because small samples mean they are less representative of the population at large. The bigger a sample is, the better estimate we will have of the parameter.

We are told that "sample A had a larger sample size" indicating that sample A has a more narrow confidence interval.

Therefore, sample B would have a wider confidence interval.

This is true regardless of what the confidence level is set at.

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What are the vertical asymptote(s) and hole(s) for the graph of y =
Murljashka [212]

Answer:

asymptotes: x= -4,-2 and no holes

Step-by-step explanation:

First we need to factor the denominator of the function

y = (x-1) / (x2 + 6x + 8)

x2 + 6x + 8 = 0

delta = b2 - 4ac = 36 - 32 = 4

x1 = (-6 + 2) / 2 = -2

x2 = (-6 - 2) / 2 = -4

So we have that x2 + 6x + 8 = (x+4)(x+2)

So our function is:

y =  (x-1) / (x+4)(x+2)

As there is no common expressions in the numerator and denominator, there are no holes.

The asymptotes are when the denominator is zero, so:

(x+4)(x+2) = 0

x = -4 or x = -2

6 0
3 years ago
Use the given functions to find f (g(x)), and give the restrictions on x.
torisob [31]

Answer:

f(g(x)) = \frac{10x-9}{3 + 3x}

Step-by-step explanation:

Given

f(x) = \frac{1}{x} - 3

g(x) = \frac{3}{x} + 3

Required

Find f(g(x))

If: f(x) = \frac{1}{x} - 3

Then:

f(g(x)) = \frac{1}{3/x + 3} -3

Solve the denominator (take LCM)

f(g(x)) = \frac{1}{\frac{3+3x}{x}} -3

f(g(x)) = \frac{x}{3 + 3x} - 3

It can be solved further as:

f(g(x)) = \frac{x-3(3 + 3x)}{3 + 3x}

f(g(x)) = \frac{x-9 + 9x}{3 + 3x}

f(g(x)) = \frac{10x-9}{3 + 3x}

4 0
3 years ago
Helppp pleaseeee I really need help
Naya [18.7K]

Answer:

Step-by-step explanation:

S

5 0
3 years ago
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What is the solution to 6x+y=24
zimovet [89]

6x+y=24

-6x to both sides

y=-6x+24

divide by 6

y=-4


I am sorry if this is wrong.

5 0
3 years ago
What is 2+2+2+2+2x^4x55
Yanka [14]

Answer: 888

Step-by-step explanation: simplify it

7 0
3 years ago
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