Evaluate the following expression 2+(3-2×2)×1
1 answer:
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Answer:
Step-by-step explanation:
p = Product of all odd integers between 500 an 598. So,
p = 501 x 503 x 505 ... x 595 x 597
q = Product of all odd integers between 500 and 602. So,
q = 501 x 503 x 505 ... x 595 x 597 x 599 x 601
From the above relations, we can see that q is equal to p multiplied by 599 and 601. i.e.
q = p x 599 x 601
or,
We need to evaluate 1p + 1q in terms of q. Using the value of p from above expression, we get: