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Readme [11.4K]
3 years ago
9

Can I get some help here?

Mathematics
1 answer:
ycow [4]3 years ago
8 0

Answer:

I dont hell know

Step-by-step explanation:

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Rita has a rope 5 m long. She cuts it into 2 pieces of length 2 m 30 cm and 1 m 65 cm.
Diano4ka-milaya [45]

Answer:

3m 95cm

Step-by-step explanation:

its... simple math? i added 2 and 1; and 30 and 65?

6 0
3 years ago
Need some help please
katovenus [111]

Answer:

the answer is 40.1 cm

Step-by-step explanation:

\cos( \alpha )  = adjacent \div hypotenuse

The adjacent in the triangle is 23cm and the Alpha is 55 degrees, so just insert the formula to find the adjacent which is x .

Tq

8 0
3 years ago
The net of a triangular prism is shown.
egoroff_w [7]
The answer is 14 and 46cm
8 0
3 years ago
A bank requires that its customers create a PIN to access their account. The pin must be 2 letters followed by 2 numbers. How ma
klio [65]

Answer:

There are 60840 unique PINS if letters can be repeated but digits cannot be repeated

Step-by-step explanation:

In total, there are 26 letters and 10 digits.

The PIN has the following format:

L - L - N - N

The letters can be repeated, so for both letters, there are 26 options.

The digits cannot be repeated. So for the first digits there are 10 options. For the second there are 9, since the first digit used cannot be repeated.

In total:

26 - 26 - 10 - 9

26*26*10*9 = 60840

There are 60840 unique PINS if letters can be repeated but digits cannot be repeated

5 0
4 years ago
A circle has centre (3,0) and radius 5. The line y = 2x + k intersects the circle in two points. Find the set
lara [203]

A circle with center (3,0) and radius 5 has equation

(x-3)^2+y^2=25 \iff x^2 + y^2- 6 x  = 16

If we substitute y=2x+k in this equation, we have

x^2+(2x+k)^2-6x=16 \iff 5x^2+(4k-6)x+k^2-16=0

This equation has two solutions (i.e. the line intersects the circle in two points) if and only if the determinant is greater than zero:

\Delta=b^2-4ac=(4k-6)^2-4\cdot 5\cdot (k^2-16)>0

The expression simplifies to

-4 (k^2 + 12 k - 89)>0 \iff k^2 + 12 k - 89

The solutions to the associated equation are

k^2 + 12 k - 89=0 \iff k=-6\pm 5\sqrt{5}

So, the parabola is negative between the two solutions:

-6-5\sqrt{5}

8 0
4 years ago
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