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kondor19780726 [428]
4 years ago
11

Y+4=0 what is the table value​

Mathematics
1 answer:
Ann [662]4 years ago
7 0

Answer:

negative 4 (-4)+4=0

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A rug is 3 feet longer than 5 times the width. The area of the rug is 92 square feet. What are the dimensions of the rug?
Rzqust [24]

Answer:

36

Step-by-step explanation:

L=W+5

Area=LW

36=(W+5)W

36=W^2+5W

W^2+5W-36=0

(W+9)(W-4)=0

W-4=0

W=4 ANS. FOR THE WIDTH.

L=4+5=9 ANS. FOR THE LENGTH.

PROOF:

36=9*4

36=36

I hope this helped! ;)

4 0
3 years ago
Read 2 more answers
Shala bought a pen on sale. She saved 17 percent of the original price of 29 dollars. About how much money did she save? A. 1 do
Gelneren [198K]

Answer:

B. 5 dollars

Step-by-step explanation:

17% = .17

"of" means to multiply.

29 × .17= 4.93

4.93 rounds up to 5

4 0
3 years ago
A rectangle has vertices E(4,8), F(2,8), G(2,-2) and H(-4,-2). The rectangle is dilated with the origin as the center of dilatio
Leona [35]

Note: The image of G after the dilation must be G'(5,-5) instead of G'(5,5).

Given:

The vertices of a rectangle are E(4,8), F(2,8), G(2,-2) and H(-4,-2).

The rectangle is dilated with the origin as the center of dilation so that G's is located at (5,-5).

To find:

The algebraic representation that represents this dilation.

Solution:

If a figure is dilated by factor k with origin as the center of dilation, then the dilation is defined as:

(x,y)\to (kx,ky)              ...(i)

Let the given rectangle is dilated by factor k with origin as the center of dilation. Then,

G(2,-2)\to G'(k(2),k(-2))

G(2,-2)\to G'(2k,-2k)

The image of G after dilation is G'(5,-5). So,

(2k,-2k)=(5,-5)

On comparing both sides, we get

2k=5

k=\dfrac{5}{2}

So, the scale factor is k=\dfrac{5}{2}.

Substituting k=\dfrac{5}{2} in (i), we get

(x,y)\to \left(\dfrac{5}{2}x,\dfrac{5}{2}y\right)

Therefore, the required algebraic representation to represents this dilation is (x,y)\to \left(\dfrac{5}{2}x,\dfrac{5}{2}y\right).

3 0
3 years ago
Find the domain of the following function below. f(x)=3x-5/2
Dmitry_Shevchenko [17]
The domain of the function would be all real numbers. (-infinity, +infinity).
The domain of a linear function is asking what are the x values and because it is a line, it goes in both directions forever. 
7 0
3 years ago
Read 2 more answers
Kiara opened an RRSP deposit account on December 1, 2008 with a deposit of $1,700. She added $1,700 on January 1, 2010, and $1,7
Angelina_Jolie [31]

Answer:

The total balance on December 1, 2016 is B = $7356.28

Step-by-step explanation:

I am going to call B1 the balance for the first deposit, B2 the balance for the second deposit and B3 for the third deposit.

This is a compound interest problem.

The compound interest formula is given by:

A = P(1 + \frac{r}{n})^{nt}

A: Amount of money(Balance)

P: Principal(Initial deposit)

r: interest rate(as a decimal value)

n: number of times that interest is compounded per unit t

t: time the money is invested or borrowed for.

First step: Balance B1 on December 1, 2016

A = amount of money =  B1

P = 1,700

r = 0.056

n = 12(compounded mothly, and t is in years)

t = 8 years

B1 = 1700(1 + \frac{0.056}{12})^{96}

B1 = $2658.17

Second step: Balance B2 on December 1, 2016

A = B3

P = 1,700

r = 0.056

n = 12(compounded mothly, and t is in years)

t: From January 1, 2010 to December 1, 2016 there are 6 years and 11 months. 11 months is 0.92 of a year. So

t = 6.92

B2 = 1700(1 + \frac{0.056}{12})^{83.04}

B2 = $2502.39

Third step: Balance B3 on December 1, 2016

A = B3

P = 1700

r = 0.056

n = 12

t: 4 years and 7 months. 7 months is 7/12 = 0.58. So t = 4.58 years.

B3 = 1700(1 + \frac{0.056}{12})^{54.96}

B3 = $2195.72

Final step: Total balance on December 1, 2016

B = 2195.72 + 2502.39 + 2658.17

B = $7356.28

So the total balance on December 1, 2016 is B = $7356.28

6 0
4 years ago
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