Answer:
I think its $28
Step-by-step explanation:
Answer:
B. (-0.5, 5.75)
Step-by-step explanation:
I graphed the equation on the graph below to find the vertex of the equation.
Answer:
B in the photo
Step-by-step explanation:
another way to write the problem:
square root is also taking the 1/2 power:

since they are raised to the same power:

Answer:
The ratio of the perimeter of ABCD to JKLM is;
b. 3/5
Step-by-step explanation:
Given that ABCD ~ JKLM, where;
DC and ML are corresponding sides
AD and JM are corresponding sides
AB and JK are corresponding sides
Therefore;
DC/ML = AD/JM = AB/JK
Plugging in the values of the variables gives;
9/15 = z/10 = x/12
∴ z = 10×9/15 = 6
x = 12×9/15 = 7.2
9/15 = 6/y
y = 6 ×15/9 = 10
The perimeter of the quadrilateral ABCD = AB + BC + DC + AD
∴ The perimeter of the quadrilateral ABCD = 6 + 6 + 9 + 7.2 = 28.2
The perimeter of the quadrilateral JKLM = JK + JM + ML + LK
∴ The perimeter of the quadrilateral JKLM = 12 + 10 + 15 + 10 = 47
The ratio of the perimeter of ABCD to JKLM = 28.2/47 =0.6 = 3/5.
Answer:your question seems incomplete but if you looking to find the resulting equation to solve for temperature at a particular time you can use this 28t^2
Step-by-step explanation:
F'(t) = 7(0.8)t
Integrating the RHS
Temp= integral of f'(t)= 28t^2
Therefore, T(°c)= 28t^2