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andre [41]
3 years ago
8

Suppose you want to factor the expression x2+ 2xn+n2. Given that n> 0, what are the factors? Explain.

Mathematics
2 answers:
cestrela7 [59]3 years ago
4 0

Answer:

\left(x+n\right)^2=(x+n)(x+n)

Step-by-step explanation:

\:x^2+\:2xn+n^2

\mathrm{Perfect\:Square\:Formula}:\quad \left(a+b\right)^2=a^2+2ab+b^2

\left(x+n\right)^2=(x+n)(x+n)

spin [16.1K]3 years ago
3 0

Answer:

(x + n)^2

Step-by-step explanation:

Okay! Let's get this going!

(x + n ) ^2 is correct because first we get

x^2 and n^2. Yet we need to add one more part to this to make it true which is x * n. We multiply this by two since according to the formula (a + b)^2 = a^2 + 2ab + b^2

:)

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