Question

Suppose you want to factor the expression x2+ 2xn+n2. Given that n> 0, what are the factors? Explain.

Answer 1

Answer:

$\left(x+n\right)^2=(x+n)(x+n)$

Step-by-step explanation:

$\:x^2+\:2xn+n^2$

$\mathrm{Perfect\:Square\:Formula}:\quad \left(a+b\right)^2=a^2+2ab+b^2$

$\left(x+n\right)^2=(x+n)(x+n)$

Answer 2

Answer:

(x + n)^2

Step-by-step explanation:

Okay! Let's get this going!

(x + n ) ^2 is correct because first we get

x^2 and n^2. Yet we need to add one more part to this to make it true which is x * n. We multiply this by two since according to the formula (a + b)^2 = a^2 + 2ab + b^2

:)